Table Find Duplicate Rows (double, char, datetime)

Hello, in table A with 100,000 rows and 40 columns, is there a way to find duplicate rows?
The elements are of the type: double, char, datetime
Thanks

Antworten (2)

the cyclist
the cyclist am 25 Okt. 2021
You might need to share some more details about your table, but you should be able to use the unique function.
% Make some pretend data, which is 8 rows with 4 unique ones
tbl = array2table([magic(4); magic(4)]);
% Find the unique rows, along with indices for identifying the duplicates
[uniqueTableRows,indexToUniqueRows,indexBackFromUnique] = unique(tbl);
See the documentation for details on the indices that are reported.

2 Kommentare

Dave
Dave am 26 Okt. 2021
Bearbeitet: Dave am 26 Okt. 2021
The table has double in some columns, char in some columns, datetime in one column
If I use unique it brings the same number of rows (and I check in excel that some rows are identical)
Different data types should not be a problem with this method:
% Make some pretend data of different types
n = [1; 2; 1; 1; 2; 1];
c = {'a';'b';'a';'b';'a';'b'};
t = datetime({'2014-05-26';'2014-08-03';'2014-05-26';'2014-08-03';'2014-05-26';'2014-08-03'},'InputFormat','yyyy-MM-dd');
% Put them in a table
tbl = table(n,c,t)
tbl = 6×3 table
n c t _ _____ ___________ 1 {'a'} 26-May-2014 2 {'b'} 03-Aug-2014 1 {'a'} 26-May-2014 1 {'b'} 03-Aug-2014 2 {'a'} 26-May-2014 1 {'b'} 03-Aug-2014
% Find the unique rows, along with indices for identifying the duplicates
[uniqueTableRows,indexToUniqueRows,indexBackFromUnique] = unique(tbl)
uniqueTableRows = 4×3 table
n c t _ _____ ___________ 1 {'a'} 26-May-2014 1 {'b'} 03-Aug-2014 2 {'a'} 26-May-2014 2 {'b'} 03-Aug-2014
indexToUniqueRows = 4×1
1 4 5 2
indexBackFromUnique = 6×1
1 4 1 2 3 2

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Abdul Rehan Khan
Abdul Rehan Khan am 12 Feb. 2025

0 Stimmen

Apart from the indices, how can store the duplicate data in a seperate table?

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Gefragt:

am 25 Okt. 2021

Beantwortet:

am 12 Feb. 2025

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