Problem using fft();

3 Ansichten (letzte 30 Tage)
atharva aalok
atharva aalok am 21 Okt. 2021
Kommentiert: atharva aalok am 21 Okt. 2021
I have a periodic signal with TimePeriod~2.3 that is f~.4347
But I am getting another peak at f = 0.
load('myData.mat');
figure(1);
plot(tSol, omegaSol);
% This is periodic with TimePeriod~2.3 or f~.4347
Fs = length(tSol) / (max(tSol)-min(tSol)); % Sampling frequency
T = 1/Fs; % Sampling period
L = Fs * (max(tSol) - min(tSol)); % Length of signal
t = (0:L-1)*T; % Time vector
Y = fft(omegaSol);
P2 = abs(Y/L);
P1 = P2(1:L/2+1);
P1(2:end-1) = 2*P1(2:end-1);
f = Fs*(0:(L/2))/L;
limit_f = f < 1;
f = f(limit_f);
P1 = P1(limit_f);
figure(2);
plot(f,P1)
title('Single-Sided Amplitude Spectrum of X(t)')
xlabel('f (Hz)')
ylabel('|P1(f)|')
Why Is there another peak at f ~ 0?

Akzeptierte Antwort

KSSV
KSSV am 21 Okt. 2021
Bearbeitet: KSSV am 21 Okt. 2021
Remove the mean from the data and then use fft.
Say A is your data, (array). For fft use:
A = A-mean(A) ;
  1 Kommentar
atharva aalok
atharva aalok am 21 Okt. 2021
Yeah lol I just realised a second after posting thanks!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Produkte


Version

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by