Search a given row array in a matrix and get position

I am trying to find the ch = ones(1,9)*178 row array in a large matrix. In that matrix, the number 178 on its own appears in many positions but I want to find the positions when the 9-element array with 178 occurs. If the matrix were A=[0 0 0 0 0 0 0 0 0 178 0 0 0 0 0; 1 2 5 3 2 4 178 5 6 2 2 2 2 2 2; 0 2 178 178 178 178 178 178 178 178 178 0 2 3 2]; the result should be row = 3, column =3. I guess ismember must be in the code but I can´t figure out how... Thanks!

Answer 1

[KSSV]

 A=[0 0 0 0 0 0 0 0 0 178 0 0 0 0 0; 1 2 5 3 2 4 178 5 6 2 2 2 2 2 2; 0 2 178 178 178 178 178 178 178 178 178 0 2 3 2];
 ch = ones(1,9)*178 ;
 for i = 1:size(A,1)
    idx = strfind(A(i,:),ch)
 end

idx =

     []


idx =

     []

idx = 3

[M Azpiroz]

Of course! Much easier than my previous trials! Thanks!