Need help With "If" statement

Hi everyone,

I have an if statement that looks like the following:

   if ( n == 0 && m == 0 )
          values = 1;
      elseif ( n < 0 || m < 0 )
          display('no')
      elseif ( n == 1 && m == 1 )  
           w11 = sqrt(3);
           values = w11*sqrt((1-cos(theta).^2))*pnmnew(m-1,m-1,theta,norm);    
      elseif (n == m )
          wmm = sqrt((2*m+1)/(2*m));
          values = wmm.*(1-cos(theta).^2).^(1/2).*pnmnew(m-1,m-1,theta,norm);
          wnm = sqrt(abs(((2*n+1)*(2*n-1))/((n+m)*(n-m))));
          wnmB = sqrt(abs(((2*(n-1)+1)*(2*(n-1)-1))/(((n-1)+m)*((n-1)-m))));
          values = wnm*(cos(
      elseif ( n ~= m )theta).*pnmnew(n-1,m,theta,norm)-(wnmB)^(-1)*pnmnew(n-2,m,theta,norm));

I was wondering how I could go from displaying "no" in the elseif statement to terminating it. I don't want it to recursion through values < 0. How would I make it so it ends when it hits that condition?

Thanks!

Answer 1

[Oleg Komarov]

See return, place it after:

display('no')

Oleg

Answer 2

[Matt Fig]

I don't know what you mean by "I don't want it to recursion through values <0."

An IF statement is not a recursive thing. If you mean you want the function evaluation to stop where the DISP statement is, put a call to RETURN there.

[Andrew]

Yes, I would like it to stop. I am using the entire function with if statements to do a recursive call so sometimes it gives me errors. For some reason when I add the return it still gives me an infinite recursion but I will try it again.

Thanks~

[Matt Fig]

In that case I would try to post the whole code, if it is not too long, and ask for help.

Answer 3

[Matt Tearle]

Do you want that to be an error condition? In which case error('no') (in place of disp) will display the message and terminate execution.