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sum of vector by group

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Yona
Yona am 3 Sep. 2014
Kommentiert: Yona am 3 Sep. 2014
i have a vector of numbers
a=[1 4 1 -3 -6 9 9 1 1 1 -1 -1 -4]
and i group them by their sign (i don't have zero, only positive and negative number); 3 positive, 2 negative, ext. so:
b=[3 2 5 3]
now i want to find the sum of each group:
res=[6 -9 21 -6]
how can i do it, without using a loop.
Note: the vector "a" can be empty, contain only positive number, only negative number, or both of them when the first number can be positive or negative. in any case it don't contain zeros.
Note2: the way i find "b" is:
b = diff([1 find(diff([0 sign(a)]==1)~=0) length(a)+1]);
b=b(b~=0);

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Sean de Wolski
Sean de Wolski am 3 Sep. 2014
Bearbeitet: Sean de Wolski am 3 Sep. 2014
a=[1 4 1 -3 -6 9 9 1 1 1 -1 -1 -4];
idx = cumsum([0 abs(diff(sign(a)))==2])+1;
res = accumarray(idx.',a.')
  1 Kommentar
Yona
Yona am 3 Sep. 2014
thanks, i didn't think to use cumsum on the difference. just a little improvement:
idx = cumsum([1 abs(diff(sign(a)))==2]);

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