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create a loop using regexp

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Nicolas
Nicolas am 13 Aug. 2014
Kommentiert: Nicolas am 13 Aug. 2014
I have imported a bench of text file into MATLAB using
list_files2load = dir(fullfile(directory1,'Mod1*));
In those files (here is an example: Mod1-A-00k.txt, Mod1-A-10k.txt, Mod1-A-30k.txt; Mod1-B-00k.txt, Mod1-B-10k.txt, Mod1-B-30k.txt), I would like to pick first only the ones that end with '*00k.txt', so I do :
a={'Mod1-A-00k.txt', 'Mod1-A-10k.txt', 'Mod1-A-30k.txt', 'Mod1-B-00k.txt', 'Mod1-B-10k.txt', 'Mod1-B-30k.txt'}
idx=~cellfun(@isempty,regexp(a,'.+(00k.txt)\>','match'))
b=a(idx)
Now I would like to know if it is possible with regexp to create a loop which first starts with piking the files ending with '*00k.txt' and in the second loop the files ending with '*10k.txt' and so on.
Thank you

Akzeptierte Antwort

Geoff Hayes
Geoff Hayes am 13 Aug. 2014
Nicolas - for sure you can add a loop as long as you know what to increment by at each iteration. If we assume an increment of 10 (given your pattern of 00,10,30) then we could wrap your above code in a for loop as
for u=0:10:50
% create the file pattern
filePattern = sprintf('%02d',u);
idx=~cellfun(@isempty,regexp(a,['.+(' filePattern 'k.txt)\>'],'match'));
% if any value in logical array is one then save to b
if any(idx)
b=a(idx)
end
end
Running the above code with your a produces the following output
b =
'Mod1-A-00k.txt' 'Mod1-B-00k.txt'
b =
'Mod1-A-10k.txt' 'Mod1-B-10k.txt'
b =
'Mod1-A-30k.txt' 'Mod1-B-30k.txt'
  1 Kommentar
Nicolas
Nicolas am 13 Aug. 2014
thank you, that's perfect.

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Weitere Antworten (1)

Christopher Berry
Christopher Berry am 13 Aug. 2014
You can do this with regular expressions, but your name requirements seem simple enough to do with dir and sprintf instead.
My suggestion would be to put the dir call inside your for loop and try something like:
for i=0:10:30
str = sprintf('Mod1*%0dk.txt',i)
list_files2load = dir(fullfile(directory1,str));
%DO WORK ON FILES HERE
end
See the documenation for sprintf here:
  1 Kommentar
Nicolas
Nicolas am 13 Aug. 2014
thanks that's also really fitting what I need. thanks for the link too.

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