Antworten (1)

Voss
Voss am 30 Apr. 2022

0 Stimmen

One way:
x = -0.02:0.0001:0.02;
y = exp(-x/0.005);
plot(x,y)
Another way:
y = @(x)exp(-x/0.005);
fplot(y,[-0.02 0.02])

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Gefragt:

am 14 Sep. 2021

Beantwortet:

am 30 Apr. 2022

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