Need help with this Matlab script question? For loop!!

1 Ansicht (letzte 30 Tage)
Dylan Flores
Dylan Flores am 29 Jul. 2014
Bearbeitet: Dylan Flores am 29 Jul. 2014
I keep getting this error 'Attempted to access x(3); index out of bounds because numel(x)=2.' It's really frustrating!!!

Akzeptierte Antwort

ES
ES am 29 Jul. 2014
You have to define x(3) as well (It should be 2 right ?), and then run the loop from x=3 and change the order of statements inside the while loop, because you set x(k) and then increment k. so for the new incremented k, x(k) will not be defined yet.
Please check:
%%Determining the golden ratio in a fibonacci sequence clear,clc % Defining the first two elements in the sequence x(1) = 1;
x(2) = 1;
x(3) = 2;
k = 3;
while (abs(x(k)./x(k-1) - x(k-1)./x(k-2))>0.001)
k = k+1;
x(k) = x(k-1) + x(k-2);
end

Weitere Antworten (1)

Robert Cumming
Robert Cumming am 29 Jul. 2014
Bearbeitet: Robert Cumming am 29 Jul. 2014
It the start of your while loop the condition includes a check on x(3), hence why you get the error.
edit: you could fix it this way:
while true
x(k) = x(k-1) + x(k-2);
k = k+1;
if (abs(x(k)./x(k-1) - x(k-1)./x(k-2))>0.001)
break
end
end

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