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Variable not recognized outside a loop

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Saad
Saad am 28 Jul. 2014
Beantwortet: Saad am 28 Jul. 2014
Dear All,
I have a simple but a long code. As you can see from the loop below, I am not a very efficient coder but my code works. However, the program does not recognize the matrix F inside the loop. How can I make the code recognize the F matrix which I need to use once the loop is finished. Thank you very much
Kind Regards
S
v=1;
for z=1:length(rc)
for j=1:length(r)
for i=1:length(n)
for k=1:length(d)
for l=1:length(s)
F(v,:)=[z, l, x];
end
end
end
end
end
  1 Kommentar
Ben11
Ben11 am 28 Jul. 2014
What do you mean by "does not recognize"? Can you show the error message you get?

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Akzeptierte Antwort

Azzi Abdelmalek
Azzi Abdelmalek am 28 Jul. 2014
Bearbeitet: Azzi Abdelmalek am 28 Jul. 2014
Why do you think F is not recognized? Type
F
you will see the result
You have maybe forgotten the incrementation of v
v=1;
for z=1:length(rc)
for j=1:length(r)
for i=1:length(n)
for k=1:length(d)
for l=1:length(s)
F(v,:)=[z, l, x];
v=v+1;
end
end
end
end
end

Weitere Antworten (3)

dpb
dpb am 28 Jul. 2014
v=1;
for z=1:length(rc)
for j=1:length(r)
for i=1:length(n)
for k=1:length(d)
for l=1:length(s)
F(v,:)=[z, l, x];
...
Set
F=zeros(maxV,length([z l x].'));
first. NB that your orientation of the vector must be column, not row or this will fail. z and x needs must be defined somewhere else, too, of course.

Saad
Saad am 28 Jul. 2014
It says " ??? Undefined function or variable 'F'."
Thanks to the output "F" I managed to build another code below the loop. Now for some reasons, F can not be used outside the loop because it is not recognized- I must have missed something. Any advice is much appreciated. Thank you
S

Saad
Saad am 28 Jul. 2014
Thank you Azzi. I did increment v but I deleted it by mistake. Thanks a lot for your help
Rgds
Saad

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