Replacing all values except NaN with column number

I'm trying to convert
53 96 87
48 94 NaN
49 95 NaN
51 98 NaN
52 99 NaN
55 100 NaN
to
1 2 3
1 2 NaN
1 2 NaN
1 2 NaN
1 2 NaN
1 2 NaN
The best I can do is this, which of course fills each column (including the NaNs).
for a = 1:size(y,2)
for b = a
y(:,a) = b;
end
end
If anyone could point me toward a function that could work that would be very helpful. I've tried ~isnan(y) and others but they only allow one input argument.

 Akzeptierte Antwort

James Tursa
James Tursa am 22 Jul. 2014
E.g.,
y = floor(rand(6,3)*100);
y(2:6,3) = nan; % test data
z = repmat(1:size(y,2),size(y,1),1);
z(isnan(y)) = nan;

1 Kommentar

Scott
Scott am 22 Jul. 2014
That's clever. I'll have to add repmat to my small repertoire. Thanks a lot, James :)

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