difference between normcdf and 1-erfc

does normcdf=1-erfc

Thank you,

Answer 1

[the cyclist]

No. Here is some simple code that creates a plot that illustrates that those two functions are not equal:

x = -5 : 0.01 : 5;

y1 = normcdf(x);
y2 = 1-erfc(x);

figure
plot(x,y1,x,y2)
legend('normcdf','1-erfc')

Answer 2

[Tri]

Thank you! After further research, looks like normcdf = 0.5*erfc(-x/(sqrt(2))