How to accept time from the user into a matrix?

1 Ansicht (letzte 30 Tage)
Febin Benjamin
Febin Benjamin am 28 Jun. 2014
Kommentiert: Azzi Abdelmalek am 28 Jun. 2014
I want to accept (say)3 time elements for example 8:30, 8:20 & 8:00 from user and store it in an array using 'datenum'. How can i achieve that? Please help.
  1 Kommentar
Febin Benjamin
Febin Benjamin am 28 Jun. 2014
I have worked out my version here if anyone needs it in future.
dateNumArray = []; %// Store datenums here
%// Enter a blank line to quit this loop
while true
timestr = input('Enter a time: ', 's');
if (isempty(timestr))
break;
end
%// Split the string up at the ':'
splitStr = strsplit(timestr, ':');
%// Read in the current date as a vector
%// Format of: [Year, Month, Day, Hour, Minute, Second]
timeRead = clock;
%// Replace hours and minutes with user prompt
%// Zero the seconds
timeRead(4:6) = [str2num(splitStr{1}) str2num(splitStr{2}) 0];
%// Convert to datenum format
dateNumArray = [dateNumArray datenum(timeRead)];
end

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Azzi Abdelmalek
Azzi Abdelmalek am 28 Jun. 2014
d=input('choose 3 time in this form 8:00 8:30 9:00 ','s')
e=datenum(regexp(d,'\S+','match'))
  2 Kommentare
Febin Benjamin
Febin Benjamin am 28 Jun. 2014
Azzi does your code mean that user can input only 3 specified time elements i.e 8:00 8:30 9:00? No right? User should be able to enter any time (e.g. 4:45 5:56 8:00).
Azzi Abdelmalek
Azzi Abdelmalek am 28 Jun. 2014
No , he can enter any number of time he wants, just choose your message

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Dates and Time finden Sie in Help Center und File Exchange

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by