How to make loop and sum the result ??

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ali
ali am 4 Jun. 2014
Kommentiert: Mahdi am 4 Jun. 2014
I have this loop...
for i=1:3
A=x((i-1)*3+1);
B=x((i-1)*3+2);
C=x((i-1)*3+3);
R=A^2+B^3+A*c;
end
i have constriants D=7 or <7
so i need this costraint=D-C-M
let say M=2
my equestion is how can i have the sumuation result of C from loop three times and then add this sum to constraint equation???
Thank you.

Akzeptierte Antwort

Mahdi
Mahdi am 4 Jun. 2014
for i=1:3
A(i)=x((i-1)*3+1);
B(i)=x((i-1)*3+2);
C(i)=x((i-1)*3+3);
R(i)=A^2+B^3+A*c;
end
Summation=sum(C);

Weitere Antworten (1)

ali
ali am 4 Jun. 2014
Thank you Mahdi for answer, but i want the result value of c in each loop after sum add to eq .. constraint =D-C( sum of result in each loop)- M
  1 Kommentar
Mahdi
Mahdi am 4 Jun. 2014
Just move the summation inside the for loop:
for i=1:3
A(i)=x((i-1)*3+1);
B(i)=x((i-1)*3+2);
C(i)=x((i-1)*3+3);
R(i)=A^2+B^3+A*c;
Summation(i)=sum(C);
end
In this case, each row of summation would correspond to the summation inside each iteration of the loop.

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