Sum of the elements of rows of matrix

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Akmyrat
Akmyrat am 28 Mai 2014
Kommentiert: Jos (10584) am 29 Mai 2014
lets say i have A=[1 2 1;3 2 1;3 5 4] and i want to sum up row elements separately and show me results as "Ri=..." here "i" is number of row. in this case R1=7, R2=9. R3=6.
  1 Kommentar
Matt J
Matt J am 28 Mai 2014
It sounds like you really mean "sum up column elements". The elements you are summing all belong to a common column, not a common row.

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Akzeptierte Antwort

Matt J
Matt J am 28 Mai 2014
Bearbeitet: Matt J am 28 Mai 2014
Asum=sum(A,1);
for i=1:length(Asum)
disp(['R' num2str(i) '=' num2str(Asum(i))]);
end
  4 Kommentare
Matt J
Matt J am 28 Mai 2014
Hurts in what way? As you recommended, I do not autogenerate separate variables R1, R2, R3,...
Jos (10584)
Jos (10584) am 29 Mai 2014
:-) Indeed, you exactly did what Akmyrat asked for ...

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Weitere Antworten (2)

Chandrasekhar
Chandrasekhar am 28 Mai 2014
sum(A')
  2 Kommentare
Matt J
Matt J am 28 Mai 2014
Bearbeitet: Matt J am 28 Mai 2014
This won't work if A is a row vector. Transposing is also expensive in computation time and memory if A is large.
Chandrasekhar
Chandrasekhar am 28 Mai 2014
Please let us know what is best way to do this?

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Jos (10584)
Jos (10584) am 28 Mai 2014
You do not want to store the results in separate variables R1, R2, etc., but rather as elements of a single variable R, with R(1), R(2), etc.
A = magic(3)
RowSum = sum(R,2)
help sum
  2 Kommentare
Akmyrat
Akmyrat am 28 Mai 2014
Hi jos, thanks. but sorry your code also not working.
Jos (10584)
Jos (10584) am 28 Mai 2014
What do you mean, "not working"? Did you read the help of sum?
May be you want to sum along rows rows, i.e., sum the elements in each column?
ColumnSum = sum(R,1)
Next time, be a little bit more specific ...

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