How can I divide a matrix by its columns ?
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Andre
am 23 Apr. 2014
Bearbeitet: the cyclist
am 23 Apr. 2014
Hi,
for example:
[ 1 35 37 29 312
1 321 421 2 34
1 329 412 32 54
.
.
.
4 421 348 48 445
4 48 49 41 394 ]
Can I segregate this matrix in small matrix based on the first column ?
Example:
A = [ 1 35 37 29 312
1 321 421 2 34
1 329 412 32 54]
B =...
C =...
D = [ 4 421 348 48 445
4 48 49 41 394 ]
Andre
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the cyclist
am 23 Apr. 2014
Bearbeitet: the cyclist
am 23 Apr. 2014
Yes, use the accepted answer from Azzi that is posted here. Just choose the 1st column instead of the 4th column.
Namely, if your original matrix is called A, then
[ii,jj,kk] = unique(A(:,1))
out = accumarray(kk,1:numel(kk),[],@(x) {A(x,:)})
celldisp(out)
You will see that "out" is a cell array, where each cell has one of the smaller matrices you want.
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