Error using plot--vectors must be the same lengths?
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Why am I getting the error message, "Error using plot Vectors must be the same lengths"? This code worked fine before I added a few more data points… Thank you in advance! :)
% Load Horiz.Disp. Vert.Disp.
A=[0.000000E+0 0.000000E+0 0.000000E+0
3.735352E-1 -5.517578E-3 -3.906250E-4
5.489746E-1 -1.005859E-2 -9.765625E-5
5.575684E-1 -1.054687E-2 7.812500E-4
5.644531E-1 -1.113281E-2 1.708984E-3
6.968750E-1 -1.381836E-2 2.734375E-3
9.428223E-1 -1.835937E-2 2.734375E-3
1.182324E+0 -2.192383E-2 4.394531E-3
1.416846E+0 -2.827148E-2 4.150391E-3
1.622949E+0 -3.500977E-2 3.906250E-3
1.815039E+0 -4.213867E-2 5.126953E-3
2.005273E+0 -5.039062E-2 5.664063E-3
2.201904E+0 -5.966797E-2 5.908203E-3
2.406152E+0 -7.031250E-2 5.859375E-3
2.622949E+0 -8.139648E-2 6.005859E-3
2.858691E+0 -9.526367E-2 5.957031E-3
3.104980E+0 -1.117676E-1 6.494141E-3
3.371484E+0 -1.316406E-1 7.226563E-3
3.663330E+0 -1.607422E-1 6.787109E-3
3.968652E+0 -1.978027E-1 7.666016E-3
4.311963E+0 -2.585937E-1 7.226563E-3
4.648584E+0 -3.464844E-1 8.251953E-3
4.933789E+0 -4.650879E-1 8.984375E-3
5.160156E+0 -6.127930E-1 9.472656E-3
5.314648E+0 -7.623535E-1 9.423828E-3
5.421826E+0 -9.119141E-1 9.814453E-3
5.497217E+0 -1.054199E+0 1.054688E-2
5.550635E+0 -1.184229E+0 1.079102E-2
5.592627E+0 -1.308594E+0 1.127930E-2
5.625293E+0 -1.420264E+0 1.191406E-2
5.677246E+0 -1.631250E+0 1.269531E-2
5.710596E+0 -1.820898E+0 1.333008E-2
5.735498E+0 -1.994336E+0 1.420898E-2
5.754199E+0 -2.154346E+0 1.552734E-2
5.777881E+0 -2.449365E+0 1.650391E-2
5.781934E+0 -2.584668E+0 1.728516E-2
5.781396E+0 -2.712500E+0 1.796875E-2
5.778418E+0 -2.836328E+0 1.948242E-2
5.776172E+0 -2.897314E+0 2.011719E-2
5.765283E+0 -3.072803E+0 2.109375E-2
5.759521E+0 -3.127002E+0 2.207031E-2
5.754980E+0 -3.183545E+0 2.304688E-2
5.733252E+0 -3.396484E+0 2.456055E-2
5.717334E+0 -3.498437E+0 2.558594E-2
5.684521E+0 -3.697021E+0 2.705078E-2
5.664746E+0 -3.790869E+0 2.783203E-2
5.633740E+0 -3.931055E+0 2.861328E-2
5.621533E+0 -3.974951E+0 2.934570E-2
5.598584E+0 -4.064502E+0 3.007813E-2
5.585693E+0 -4.108057E+0 3.081055E-2
5.573096E+0 -4.152197E+0 3.159180E-2
5.535010E+0 -4.279150E+0 3.247070E-2];
load=(A(:,1)).*100;
HorizDisp=abs((A(:,2)).*0.19574);
VertDisp=abs((A(:,3)).*1.724);
l=length(load);
yield=40000; %yield stress = 40 ksi
b=.125; %b = t = thickness of rod
h=1; %h = w = width of rod
L=9.875; %L = length of rod (subtracted out 2 in from 11.875)
E=10000000; %elastic modulus of Al 6061-T6
I=h*(b^3)/12; %Moment of Intertia
P=E*I*4*pi*pi/(L*L); %Buckling (or "critical") Load
disp(P) %Display value of Buckling Load
for n=1:l
loadnorm(n)=load(n)/P; %Normalize applied load by dividing by P
end
plot(VertDisp,loadnorm);
1 Kommentar
the cyclist
am 22 Apr. 2014
Side note: You should avoid naming a variable "load", because that is a MATLAB keyword.
[Not related to your present difficulty, most likely, but just good programming practice.]
Antworten (2)
Joseph Cheng
am 22 Apr. 2014
Plotted with mine as well. Kelsey can you tell us what dimensions (mxn) VertDisp and loadnorm are that you have in the work space?
Have you attempted to clear the workspace. Perhaps in your trouble shooting a dimension in either variable got screwed up.
2 Kommentare
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