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How to retain only the rows of a matrix based on the unique numbers in the first column of the matrix?

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Hello guys Say that a=[1 3 3; 1 4 3; 2 4 3; 2 5 2; 2 4 2; 3 2 1; 4 3 4; 4 3 2] I need to keep the rows where I have only unique numbers in the first column of the matrix. That means I want to have this matrix a= [1 3 3; 2 4 3; 3 2 1; 4 3 4]. Or I also need to get [1 4 3; 2 4 2; 3 2 1; 4 3 2]. That means retaining the last unique row (based on only the first column) instead of the first. Are they possible? please help.
Kind regards
Sayeed

Akzeptierte Antwort

Azzi Abdelmalek
Azzi Abdelmalek am 22 Apr. 2014
Bearbeitet: Azzi Abdelmalek am 22 Apr. 2014
[ii,jj,kk]=unique(a(:,1),'stable');
out1=a(jj,:)
out2=cell2mat(accumarray(kk,1:numel(kk),[],@(x) {a(max(x),:)}));
  1 Kommentar
Mohammad Sayeed
Mohammad Sayeed am 22 Apr. 2014
Dear Brother It was just perfect! Thank you very much for your kind solution. By applying your codes, I have got both the matrix that I was looking for. Thanks again.
Sayeed

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Andrei Bobrov
Andrei Bobrov am 22 Apr. 2014
Bearbeitet: Andrei Bobrov am 22 Apr. 2014
[~,b] = unique(a(:,1),'first');
out1 = a(b,:);
out2 = a([b(2:end)-1;size(a,1)],:);
or
[~,b1] = unique(a(:,1),'first');
[~,b2] = unique(a(:,1),'last');
out1 = a(b1,:);
out2 = a(b2,:);

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