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Data size mismatch..

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Anandh
Anandh am 29 Jul. 2011
Dear friends, I have tried to execute the below mentioned code. But am getting following error: _*E_rror using ==> mle at 208 DATA must be a vector.
Error in ==> MixtureModelExample_test at 31 p = mle(data, 'pdf', mixtureGauss, 'start', [0.5 0.1 0.5 0.1 0.5], ..._ _*
How to correct the code? whats wrong in this? Please help me out. thanks.
function MixtureModelExample() % % This script generates some data from two different Gaussians and then % combines the data into one big vector. It then fits a mixture model of % two Gaussians to the data to try to recover the original Gaussians that % generated the data (it uses the matlab function mle() to get the maximum % likelihood mixture). % %
% Generate some data drawn from two Gaussians
a=[8.3 13.9 12.5 22.2 8.3 11.1 18.1 11.1 6.9 6.9 6.9 19.4 9.7 4.2 5.6 12.5 11.1 6.9 8.3 8.3 13.9 9.7 6.9 6.9 8.3 5.6 12.5 4.2 18.1 11.1 4.2 8.3 12.5 15.3 5.6 6.9 13.9 13.9 18.1 12.5 15.3 29.2 36.1 30.6 22.2 40.3 41.7 52.8 50 52.8 61.1 55.6 72.2 69.4 68.1 68.1 76.4 94.4 77.8 101.4 81.9 73.6 93.1 76.4 48.6 52.8 41.7 44.4 43.1 25 26.4 19.4 25 19.4 16.7 13.9 8.3 15.3 5.6 5.6 5.6 5.6 9.7 6.9 2.8 8.3 9.7 8.3 11.1 12.5 15.3 8.3 13.9 4.2 16.7 5.6 8.3 16.7 4.2 11.1 2.8 8.3 5.6 8.3 4.2 11.1 12.5 8.3 8.3 9.7 13.9 15.3 19.4 20.8 25 23.6 25 25 25 33.3 26.4 23.6 27.8 19.4 22.2 19.4 23.6 26.4 15.3 23.6 15.3 26.4 13.9 9.7 15.3 11.1 11.1 18.1 9.7 16.7 18.1 9.7 11.1 22.2 18.1 13.9 19.4 20.8 18.1 13.9 15.3 19.4 13.9 16.7 20.8 12.5 18.1 15.3 15.3 12.5 8.3 12.5 20.8 15.3 15.3 12.5 13.9 9.7 18.1 8.3 19.4 16.7 12.5 12.5 13.9 6.9 9.7 11.1 16.7 5.6 8.3 11.1 4.2 12.5 2.8 12.5 11.1 8.3 9.7 8.3 8.3 18.1 12.5 11.1 8.3 9.7 6.9 12.5 5.6 8.3 0];
b=[a.*1.1];
data = [a;b]';
data(data < 0.05) = 0.05;
[n,x] = hist(data);
bar(x,n);
% Make the mixture model pdf
mixtureGauss = ...
@(x,m1,s1,m2,s2,theta) (theta*normpdf(x,m1,s1) + (1-theta)*normpdf(x,m2,s2));
% Set up parameters for the MLE function
options = statset('mlecustom');
options.MaxIter = 20000;
options.MaxFunEvals = 20000;
% Get max likilihood parameters for our mixture model (start with some
% reasonable guesses about the parameters)
p = mle(data, 'pdf', mixtureGauss, 'start', [0.5 0.1 0.5 0.1 0.5], ...
'lowerbound', [-Inf 0 -Inf 0 0], 'upperbound', [Inf Inf Inf Inf 1], ...
'options', options);
% Plot and print information
hold on;
x = linspace(min(data),max(data),100);
plot(x, mixtureGauss(x,p(1),p(2),p(3),p(4),p(5))*max(n), 'r', 'LineWidth', 2);
fprintf('Gauss 1: %0.2f (+/- %0.2f)\n', p(1), p(2));
fprintf('Gauss 2: %0.2f (+/- %0.2f)\n', p(3), p(4));
fprintf('Mix: %0.2f proportion first gaussian\n', p(5));

Akzeptierte Antwort

Andrew Newell
Andrew Newell am 29 Jul. 2011
The function mle expects data to be a vector. Use
p = mle(data(:,2), ...
instead of
p = mle(data, ...
  1 Kommentar
Anandh
Anandh am 1 Aug. 2011
thank you very much friends. useful information.

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Weitere Antworten (1)

Rob Graessle
Rob Graessle am 29 Jul. 2011
Assuming you want "data" to be the row vector "b" appended to row vector "a" to create one long row vector:
data = [a;b]';
should instead be
data = [a, b]';
for horizontal concatenation.
  1 Kommentar
Andrew Newell
Andrew Newell am 30 Jul. 2011
Good point. Your assumption is probably correct, given b=[a.*1.1];

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