Operands to the || and && operators must be convertible to logical scalar values.
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%Code x=[1.01 ;2.23; 3.456 ;4.11; 5.897 ;6.234; 7.456; 8.567; 9.110; 10.333];
a=0;
if((x>=5.2)&&(x<=8.50))
disp('Inside if loop');
a=a+1;
end
a
I want the no of values greater than some value and less than some value in a 1D array. If i am going for if statement with sysntax if((x(:,1)>=5.2)&&(t(:,1)<=8.50)) i am getting Operands to the and && operators must be convertible to logical scalar values error.
If i use if((x(:,1)>=5.2)&(t(:,1)<=8.50)) flow is not going inside the loop and i am not able to get the count as 3 .
1 Kommentar
Image Analyst
am 10 Apr. 2014
You don't have a loop at all! There is no "for" and an "if" block is not a loop.
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Weitere Antworten (3)
Marta Salas
am 10 Apr. 2014
Bearbeitet: Marta Salas
am 10 Apr. 2014
find returns the indexes of the values that holds the condition 5.2=< x >=8.50
index = find(x>=5.2 & x<=8.50)
To know the number of values, you can check the size of index
length(index)
2 Kommentare
Thayumanavan
am 10 Apr. 2014
Marta Salas
am 10 Apr. 2014
That code works for me.
I would suggest you to use fprintf instead of disp to print comments with variables
fprintf('the count is %d \n',a);
Horia
am 18 Mai 2014
0 Stimmen
Try: if condition 1 do something else if condition 2 do the samething; else do something else break; end; end;
sai m
am 3 Mär. 2015
0 Stimmen
if(get(handles.radiobutton1,'Value') == 0 && get(handles.radiobutton2,'Value') == 0 && get(handles.radiobutton5,'Value') == 0 && get(handles.radiobutton6,'Value' == 0 && get(handles.radiobutton7,'Value') == 0 && get(handles.radiobutton8,'Value') == 0 && get(handles.radiobutton9,'Value') == 0 && get(handles.radiobutton10,'Value') == 0)) errordlg('No option selected','File Error'); %user did not select any radio button, then do this guidata(hObject, handles); end;
error ??? Operands to the and && operators must be convertible to logical scalar values.
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