fill part of vector

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yousef Yousef
yousef Yousef am 9 Apr. 2014
Kommentiert: dpb am 9 Apr. 2014
I have a=[1 2 5 4 2 7 4 8 2 3](10 values),b=[0 1 2 3],I want to fill a so that
a=[0 1 2 3 0 0 0 0 0 0],

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dpb
dpb am 9 Apr. 2014
There's nothing left so there's no point in doing anything except sotoo--
a=0; a(1:length(b))=b;
a=[b zeros(1,length(a)-length(b)];
An essentially innumerable ways to get there, choose one and go on.
  3 Kommentare
dpb
dpb am 9 Apr. 2014
so fix the typo of I forgot that '0' is a scaler and won't fill...
a=zeros(size(a)); a(1:length(b)=b;
surely that's not too tough.
yousef Yousef
yousef Yousef am 9 Apr. 2014
its perfect.Thanks a lot

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yousef Yousef
yousef Yousef am 9 Apr. 2014
assume I have d=[1 3 5 6 7 8 1 4 5 10],e=zeros(5,10),I want to take only the first 4 elements of d and fit them to the first row of e
  1 Kommentar
dpb
dpb am 9 Apr. 2014
Basically the same thing--just use colon operator to address the elements of concern ensuring the LHS and RHS have same length of subscripting.
All of these kinds of operations are in the "Getting Started" section of the documentation under array addressing. I suggest working thru those early sections and the exercises/examples therein to get the basics down.

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