Creating Matrix using nested for loop?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
how would i create the following matrix using a nested for loop?
[3 6 9 12 15;
4 8 12 16 20;
7 14 21 28 35]
so far i have: m=3;
n=5;
C=zeros(m,n);
for j=1:n
for i=1:m
C(i,j) =
end
end
2 Kommentare
Antworten (3)
Azzi Abdelmalek
am 6 Apr. 2014
Maybe you want this
n=5;
m=6;
out=cell2mat(arrayfun(@(x) x:x:n*x,(1:m)','un',0))
0 Kommentare
Roger Stafford
am 7 Apr. 2014
How about
C = [3;4;7]*(1:5);
or
C = zeros(3,5);
for r = [3,4,7]
for c = 1:5
C(r,c) = r*c;
end
end
1 Kommentar
Alberto
am 7 Apr. 2014
m=3; n=5; C=zeros(m,n); A=[3 4 7]; for k=1:length(A) for j=1:5 C(k,j)= A(k)*j end end
Lam Nguyen Van
am 10 Mär. 2020
Hi,
I want to creat matrices automatically with for loop in Matlab?
phi1=30; phi2=45; phi3=90;
After running the code I want to have a matric A with the following elements:
A=[sin(phi1) cos(phi1) sin(phi1)*cos(phi1);
sin(phi2) cos(phi2) sin(phi2)*cos(phi2);
sin(phi3) cos(phi3) sin(phi3)*cos(phi3);]
Thanks.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!