Slope of a line

I'm trying to find the slope of this line

line([newBoxPolygon(1, 1) newBoxPolygon(4, 1)],[newBoxPolygon(1, 2) newBoxPolygon(4, 2)],'Color','G');
%Slope
X = (max([50 50])-min([50 50]));        
Y=(max([1 10000])-min([1 10000]));
Slope_Reference=Y/X;
disp('Slope_Reference:');disp(Slope_Reference);

Is the slope i'm obtaining correct ?

Answer 1

[Mischa Kim]

In general, your equation is correct, k = dY/dX, however, in

 X = (max([50 50])-min([50 50]));         % 50 - 50 = 0
 Y = (max([1 10000])-min([1 10000]));

X = 0 resulting in a slope of Inf. So I am wondering what you are trying to compute the slope of.

Answer 2

[Paul]

(max([50 50])-min([50 50]))

returns 0, since the minimum and maximum of the vector [50 50] is 50. This means that X=0 and thus Y/X = Y/0 = inf.