having trouble with for loops

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Joseph
Joseph am 13 Feb. 2014
Having Trouble...
'Sum of N^2 with N = 1 to 1,000 using a for loop'

Akzeptierte Antwort

Andrei Bobrov
Andrei Bobrov am 13 Feb. 2014
out = 1;
for ii = 2:1000
out = out + ii^2;
end
  3 Kommentare
Thomas
Thomas am 13 Feb. 2014
what answer do u expect?
Joseph
Joseph am 13 Feb. 2014
i got it thanks

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Weitere Antworten (2)

Roger Stafford
Roger Stafford am 13 Feb. 2014
Here's a way to check your answer:
n = 1000;
s = n*(n+1)*(2*n+1)/6;
This gives you the same value as
s = sum((1:n).^2);

Alonso Mukendi Kalonji
Alonso Mukendi Kalonji am 29 Okt. 2022
a = 1;
n= 1000;
for i = 1: n
a = a+i^2
end
disp(a)

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