Filter löschen
Filter löschen

Summation loop (sigma notation) help

6 Ansichten (letzte 30 Tage)
S
S am 10 Feb. 2014
Kommentiert: S am 10 Feb. 2014
Please help! I am slowly but surely understanding Matlab, but struggle a bit every now and then. I am trying to make a summation loop out of:
a=1:100; n=2; sum_a=0.5; for ii=1:length(a); sum_a=sum_a + a(ii).^n; end display(sum_a);
The way i read it is that (a)^n + (a+a)^n + (a+a+a)^n....
Is this correct?
Many thanks :D

Antworten (3)

ES
ES am 10 Feb. 2014
Bearbeitet: ES am 10 Feb. 2014
What yours does is sum of squares of natural numbers from 1 to 1000 +0.5. That is 0.5+1^2+2^2+3^2+...+1000^2;
Is this what you want?
  1 Kommentar
S
S am 10 Feb. 2014
No i want the 0.5 to be the first number and then it goes up in powers of 2 till infinite ;/

Melden Sie sich an, um zu kommentieren.


Mischa Kim
Mischa Kim am 10 Feb. 2014
In your code
sum_a = 0.5;
for ii = 1:length(a)
sum_a = sum_a + a(ii).^n;
end
you initially set sum_a = 0.5. In the loop you then add a(ii).^n to the previously stored value of sum_a. In other words:
ii = 1: sum_a = 0.5 + 1^2 ... which equals 1.5
ii = 2: sum_a = 1.5 + 2^2 ... which equals 5.5
ii = 3: sum_a = 5.5 + 3^2 ... which equals 14.5
...

Iain
Iain am 10 Feb. 2014
If you want: (a)^n + (a+a)^n + (a+a+a)^n....
What you actually want is:
a = 0.5; % or whatever
sum = 0;
n = 2;
for i = 1:m % m being the limit
sum = sum + (i*a)^n
end
So, if m is 0, you get sum = 0, if m is 1, you get 0.25, if m is 2, sum = 1.25, m = 3, sum = 3.5, m = 4 sum = 7.5 ...

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by