Discretise into Equal Intervals
10 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
simply90
am 21 Jan. 2014
Kommentiert: simply90
am 21 Jan. 2014
I have an array of data, 2 columns and 19 rows of entries, which can be plotted as a loglog curve. However, the x-data I have does not have standard intervals and I need to approximate the curve as a piecewise linear function. Any suggestions as to how to go about this?
6 Kommentare
Akzeptierte Antwort
Bruno Pop-Stefanov
am 21 Jan. 2014
Bearbeitet: Bruno Pop-Stefanov
am 21 Jan. 2014
You can use several methods to interpolate data points from non-uniformly spaced points. There are listed here for one dimension:
vq = interp1(c, v, xq)
where x are the (non-uniformly spaced) input points (the first row in your vector) with values v (the second row in your vector), and xq are the query points (your uniformly spaced points). The function returns the interpolated values at xq in the vector vq.
For uniformly-spaced query points, you can use:
x_begin = x(1,1); % your 0.005
x_end = x(end,1); % your 2.13
numPoints = numel(x(:,1)); % number of points in your original vector; you can change that
xq = linspace(x_begin, x_end, numPoints);
for numPoints linearly spaced between x_begin and x_end. If you prefer to specify the length of each interval instead of the number of points, you could write:
xq = x_begin : int_length : x_end;
with int_length = 0.07.
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Get Started with Curve Fitting Toolbox finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!