Research question : how to compute chirality by DIV & CURL function

2 Ansichten (letzte 30 Tage)
chi shing
chi shing am 21 Jan. 2014
Kommentiert: Roger Stafford am 23 Jan. 2014
----------------------------------
[X Y Z] = meshgrid(y,x,z);
[cx1,cy1,cz1] = curl(X,Y,Z,Ex,Ey,Ez);
div1 = divergence(X,Y,Z,cx1,cy1,cz1);
term1 = 8.854*10^-12*0.5*div1;
[cx2,cy2,cz2] = curl(X,Y,Z,Hx,Hy,Hz);
div2 = divergence(X,Y,Z,cx2,cy2,cz2);
term2 = (1/(4*pi*10^-7))*0.5*div2;
chirality = term1 + term2;
----------------------------------
The above are my script to calculate chirality However, all Ex,Ey,Ez,Hx,Hy,Hz are complex number, but I already to transfer to real number. Should I use complex or real? Any error in syntax?
  1 Kommentar
chi shing
chi shing am 21 Jan. 2014
Thank you Matt J to help me editing the format
By the way, I forgot to upload the related equation

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Roger Stafford
Roger Stafford am 21 Jan. 2014
As far as I can see, the equation you show does not contain any divergence operations. One term is the scalar (dot) product of the electric field, E, by its curl, and the other term the same with the magnetic field, B. I see no divergence here. The divergence of the curl would imply the presence of second partial derivatives and there are none in the equation. In any case, the divergence of the curl of any vector field would always be identically zero.
  2 Kommentare
chi shing
chi shing am 22 Jan. 2014
Sorry about the unclear question. In fact, I wanna to show that DIV of CURL of vector should be zero, so that it can ensure my syntax is correct. One more question is that if all Ex,Ey,Ez,Hx,Hy,Hz are complex number, the above result will still get zero?
Roger Stafford
Roger Stafford am 23 Jan. 2014
Yes, the divergence of the curl of a vector field with continuous second derivatives with respect to position coordinates will always be zero even if this vector field is complex-valued.

Melden Sie sich an, um zu kommentieren.

Tags

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by