Error simple program PID

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JOJO
JOJO am 15 Jan. 2014
Bearbeitet: JOJO am 27 Mai 2014
Hello, I doing a pid project I have everything correct but this error come up what I should do?

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JOJO
JOJO am 15 Jan. 2014
in my second compute it works, however I dont know how to find the tooboxes
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Mischa Kim
Mischa Kim am 15 Jan. 2014
Type
which -all syms
and you should get something like
C:\Program Files\MATLAB\R2013b\toolbox\symbolic\symbolic\syms.m

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Weitere Antworten (5)

Mischa Kim
Mischa Kim am 15 Jan. 2014
Interesting. The code is just fine.
Try this: copy-and-paste the code from your question above and paste it into the MATLAB command window. Execute.
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Mischa Kim
Mischa Kim am 15 Jan. 2014
I assume you have the Symbolic Toolbox licensed?
Also, please post comments as comments.

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JOJO
JOJO am 15 Jan. 2014
I tried it give me this error I dont know why

David Sanchez
David Sanchez am 15 Jan. 2014
I tried your code (copy-paste) and it works. Make sure you have the Symbolic Math toolbox:
Start (bottom left corner)-> Toolboxes
You should see the all the toolboxes of your system, if you do not locate the Symbolic Math toolbox, you can not use
syms

JOJO
JOJO am 15 Jan. 2014
Bearbeitet: JOJO am 2 Feb. 2014
I used control theory it worked.
Thanks Davi

Carla
Carla am 15 Jan. 2014
Is there a reason you need to do this with syms? At least in the code you showed, it doesn't look like you are using any Symbolic Toolbox functionality. You can achieve the same exact result using only Control System Toolbox as follows:
num=1; % Numerator
den=[1,3,1]; % Denominator
G=tf(num,den); % Transfer Function
H=1; % Negative Feedback Loop with Unity Feedback
Kp=1; % Increment these three varaibles to give desired output
Ki=0;
Kd=0;
C=pid(Kp,Ki,Kd); % Controller Function
T=feedback(C*G,H); % C in series with G with negative feedback H
step(T) % Step Response with Controller
If there is some reason elsewhere in your program that you need syms functionality, I suppose this won't solve your problem!

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