Error simple program PID
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hello, I doing a pid project I have everything correct but this error come up what I should do?
0 Kommentare
Akzeptierte Antwort
JOJO
am 15 Jan. 2014
1 Kommentar
Mischa Kim
am 15 Jan. 2014
Type
which -all syms
and you should get something like
C:\Program Files\MATLAB\R2013b\toolbox\symbolic\symbolic\syms.m
Weitere Antworten (5)
Mischa Kim
am 15 Jan. 2014
Interesting. The code is just fine.
Try this: copy-and-paste the code from your question above and paste it into the MATLAB command window. Execute.
1 Kommentar
Mischa Kim
am 15 Jan. 2014
Also, please post comments as comments.
David Sanchez
am 15 Jan. 2014
I tried your code (copy-paste) and it works. Make sure you have the Symbolic Math toolbox:
Start (bottom left corner)-> Toolboxes
You should see the all the toolboxes of your system, if you do not locate the Symbolic Math toolbox, you can not use
syms
0 Kommentare
Carla
am 15 Jan. 2014
Is there a reason you need to do this with syms? At least in the code you showed, it doesn't look like you are using any Symbolic Toolbox functionality. You can achieve the same exact result using only Control System Toolbox as follows:
num=1; % Numerator
den=[1,3,1]; % Denominator
G=tf(num,den); % Transfer Function
H=1; % Negative Feedback Loop with Unity Feedback
Kp=1; % Increment these three varaibles to give desired output
Ki=0;
Kd=0;
C=pid(Kp,Ki,Kd); % Controller Function
T=feedback(C*G,H); % C in series with G with negative feedback H
step(T) % Step Response with Controller
If there is some reason elsewhere in your program that you need syms functionality, I suppose this won't solve your problem!
0 Kommentare
Siehe auch
Kategorien
Mehr zu Symbolic Math Toolbox finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!