Hi,
c=[5 7 1 9 10]; I want to create a cell from this vector as:
d={[5 7 1] [7 1 9] [1 9 10]};
Thanks in advance.

Antworten (2)

Azzi Abdelmalek
Azzi Abdelmalek am 29 Dez. 2013
Bearbeitet: Azzi Abdelmalek am 29 Dez. 2013

0 Stimmen

c=[5 7 1 9 10];
m=3;
out=arrayfun(@(x) c(x:x+m-1),1:numel(c)-m+1,'un',0)

4 Kommentare

allnab
allnab am 30 Dez. 2013
hi, it does not give the desired result {out} cell
allnab
allnab am 30 Dez. 2013
{out} cell
What do you mean? The result is exactly what you asked for. to see the result type
celldisp(out)
allnab
allnab am 30 Dez. 2013
Excuse me it works correctly now
thank you

Melden Sie sich an, um zu kommentieren.

Andrei Bobrov
Andrei Bobrov am 29 Dez. 2013

0 Stimmen

d = num2cell(c(hankel(1:3,3:numel(c))),2)

3 Kommentare

allnab
allnab am 30 Dez. 2013
hi, error message:
??? Attempted to access r(1); index out of bounds because numel(r)=0.
Error in ==> hankel at 26 elseif c(nc) ~= r(1)
This error is shown when the second input to hanker is empty:
hankel(1:3,[])
In the code above this occurs because,
  • 3:numel(c) is empty, because,
  • numel(c) is less then 3, so,
check the contents of c !
allnab
allnab am 30 Dez. 2013
Excuse me it works correctly now
thank you

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Matrices and Arrays finden Sie in Hilfe-Center und File Exchange

Tags

Gefragt:

am 29 Dez. 2013

Kommentiert:

am 30 Dez. 2013

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by