Problem using ezplot function
5 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I am having a for loop. I want to draw a graph using ezplot for a function like this: f(x) = sin(x) (0<x<pi/4) f(x) = cos(x) (pi/4<x<pi/2) that is the function is having different definition at different intervals. But, I am getting the graph in two separate figures instead of one figure. Please help.
A part of the code is provided below: syms x t1 = 0; for i = 1:n t2 = t1+L(i); if option(i)==1 R(i)=(-(M(i,1)+M(i,2))+q(i)*L(i)^2/2)/L(i); Vx = R(i)-q(i)*x; else R(i)=(-(M(i,1)+M(i,2))+q(i)*L(i)^2/3)/L(i); qx = (1-x/L(i))*q(i); Vx = R(i) - 0.5*(qx+q(i))*x; end figure; hold on; ezplot(Vx,[t1 t2]); t1 = t1+L(i); end
1 Kommentar
sixwwwwww
am 11 Dez. 2013
values of n, L, option etc. are missing. Please include these values so that your code can run properly
Antworten (1)
sixwwwwww
am 11 Dez. 2013
replace this:
figure; hold on;
ezplot(Vx,[t1 t2]);
with
ezplot(Vx,[t1 t2]), hold on
It will keep the old plot as it is and will add new plot to the same figure
0 Kommentare
Siehe auch
Kategorien
Mehr zu Bounding Regions finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!