How to use str2func to replace eval command?

I want user to enter a parametrized function in terms of t. Is there a way that I can have an input function instead of using '' and eval?
t = linspace(0.001,2,1000);
T = t;
x_e = 't.^3';
y_e = 'exp(t)';
z_e = 'cos(10*t)';
x = eval(x_e);
y = eval(y_e);
z = eval(z_e);

 Akzeptierte Antwort

Walter Roberson
Walter Roberson am 4 Dez. 2013
Bearbeitet: Walter Roberson am 4 Dez. 2013

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fx = str2func(['@(t) ', x_e]);
x = fx(t);

3 Kommentare

Matthew
Matthew am 4 Dez. 2013
Bearbeitet: Walter Roberson am 4 Dez. 2013
I tried your way and it gave me an error
This is my code
t = linspace(0.001,2,1000);
T = t;
x_e = input ('x_e');
y_e = input ('y_e');
z_e = input ('z_e');
fx = str2func(['@(t) ', x_e], 't');
x = fx(t);
fy = str2func(['@(t) ', y_e], 't');
y = fy(t);
fz = str2func(['@(t) ', z_e], 't');
z = fz(t);
and this is what the command window said
Error using str2func
Too many input arguments.
Error in test (line 6)
fx = str2func(['@(t) ', x_e], 't');
Thx
Sorry, corrected. After I put in the bad code I checked the documentation and then forgot to fix the mistake before sending.
Hi Matthew and Walter!
t = linspace(0.001,2,1000);
x_e = 't.^3';
y_e = 'exp(t)';
z_e = 'cos(10*t)';
funs = cellfun(@str2func,strcat('@(t),{x_e,y_e,z_e}),'un',0);
rez = cellfun(@(q)q(t),funs,'un',0);
[x,y,z] = rez{:};

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Weitere Antworten (1)

Andrei Bobrov
Andrei Bobrov am 4 Dez. 2013

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t = linspace(0.001,2,1000);
x_e = 't^3';
y_e = 'exp(t)';
z_e = 'cos(10*t)';
funs = arrayfun(@matlabFunction,sym({x_e,y_e,z_e}),'un',0);
rez = cellfun(@(q)q(t),funs,'un',0);
[x,y,z] = rez{:};

2 Kommentare

Walter Roberson
Walter Roberson am 4 Dez. 2013
Bearbeitet: Walter Roberson am 4 Dez. 2013
Notice here that Andrei had to change
x_e = 't.^3';
to
x_e = 't^3';
This is because sym() interprets strings as being in MuPAD language, which is slightly different than MATLAB itself. str2func() uses MATLAB language. matlabFunction() knows to convert MuPAD symbols into MATLAB language.
Matthew
Matthew am 4 Dez. 2013
Thanks I tried both of your ways and both of them work.

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