How can I add the average of two consecutive numbers?

How can I put this in a simpler form?

Area=(y(1)+y(2)/2+(y(2)+y(3)/2+(y(3)+y(4)/2+(y(4)+y(5))/2

Answer 1

[David Sanchez]

n = length(y);
Area = 0;
for k=1:(n-1)
   Area = Area + (y(k) +y(k+1))/2;
end

Answer 2

[Andrei Bobrov]

y = randi(10,5,1);

Area = sum(conv2(y,[1;1]/2,'valid'));

[Marcela Ruiz de Chávez]

It doesn't give me the right answer. I have this:

x0=1; x14=15; xr=x0:1:x14; y=A*xr.^3+B*xr.^2+C*xr+D; y_m=randi(10,15,1); Area=sum(conv2(y_m,[1;1]/2,'valid'))

[Andrei Bobrov]

What should be correctly?

[Marcela Ruiz de Chávez]

I solved it. Thank you!!

Answer 3

[Chibuzo Nnonyelu]

By using indexing and simple maths (y1 + y2)/2 = (y2 - y1)/2 + y1 therefore, you can do this as

Area = diff(y)/2 + y(1, end - 1)