Filter löschen
Filter löschen

Finding the norm of a matrix using for-loops and conditional statements

3 Ansichten (letzte 30 Tage)
Alright, so I'm having a bit of trouble with an example for MATLAB. I'm trying to find the conditional number of any square matrix, which normally isn't too difficult. However, instead of using the norm function to find the norm of the matrix, I am to use loops and conditional statements. I'm not completely sure where to start.
I know how to find the norm on paper - I take the absolute value of each number of the matrix, then add up the columns. The largest number, then, is the norm of the matrix. How might I translate that over into MATLAB?
EDIT: This is how what I've gotten thus far. The sums make sense, but I don't know how to edit it so that it'll work for any square matrix.
A= [2 3 4; 4 7 6; -11 85 9;];
invA= inv(A);
mn=size(A);
n=length(A);
for i=1:1:n-2
for j=1:1:n-2
sum_1=abs(A(i,1)) + abs(A((i+1),1) + abs(A((i+2),1)))
sum_2=abs(A(i,2)) + abs(A((i+1),2)) + abs(A((i+2),2))
sum_3=abs(A(i,3)) + abs(A((i+1),3)) + abs(A((i+2),3))
end
end
  3 Kommentare
Chris
Chris am 24 Nov. 2013
I'm supposed to use loops and conditional statements - I can't use max/cond/sum/similar commands.
Matt J
Matt J am 24 Nov. 2013
Bearbeitet: Matt J am 24 Nov. 2013
I know how to find the norm on paper - I take the absolute value of each number of the matrix, then add up the columns.
That is the L1 norm, not the more standard L2 norm.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Matt J
Matt J am 24 Nov. 2013
Bearbeitet: Matt J am 24 Nov. 2013
Hint:
B=abs(A);
accum=0;
for i=1:size(B,1)
accum=accum+B(i,:);
end
  2 Kommentare
Chris
Chris am 24 Nov. 2013
That makes sense, I appreciate it. What does the : signify in the B(i,:); portion?

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Chris
Chris am 25 Nov. 2013
I greatly appreciate that little hint you gave me - that little nudge in the right direction was just what I needed.

Kategorien

Mehr zu MATLAB finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by