is this a matlab bug?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
when i write like:
n = datenum('2017-06-12','yyyy-mm-dd',1900);
n = datenum('2017-06-12','yyyy-mm-dd',2000).
it return the same result.
the matlab version is r2013b.
what's the problem?
0 Kommentare
Akzeptierte Antwort
David Sanchez
am 22 Nov. 2013
The pivot year is used in interpreting date strings that have the year specified as two characters. To see the difference, introduce the last two digits of your your year, otherwise, the use of pivotyear yields the same result.
>> n1 = datenum('17-06-11','yy-mm-dd',1900)
n1 =
700332
>> n2 = datenum('17-06-11','yy-mm-dd',2000)
n2 =
736857
2 Kommentare
Fox
am 27 Jan. 2014
the two statements you have are the same: you have specified the full year '2017'. David specifies only the 3 and 4 characters, '17'. thus Matlab doesn't know if it's 2017 or 1917.
Took me way too long, but I finally found a way to navigate around this; I had data from about 1954 to now... so I wanted some pivot years as 1900 and some as 2000, and the data is not (and should not be) sorted. I told everything that the pivot year was 2000, so that I had a lot of "2054"'s etc.
m = datenum(datestamp,2000)
then in the next statement
datenum(m(m>datenum(now),:),1900);
setting values of m which are greater than today back to 1900. obviously if you have a 1912 or something, though, this would not be ok.
would love a good solution. i think i'm not seeing the tree from the forest anymore on this...
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Dates and Time finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!