How can I plot multiple signals with unit step signal

I need to plot this function:

v(t)=(2t+1)[u(t)-u(t-1)]+3[u(t-1)-u(t-2)]+(-t+3)[u(t-2)-u(t-3)]

Answer 1

[Azzi Abdelmalek]

t=-5:0.1:5
v=(2*t+1).*(heaviside(t)-heaviside(t-1))+3*(heaviside(t-1)-heaviside(t-2))+(-t+3).*(heaviside(t-2)-heaviside(t-3))
plot(t,v,'linewidth',4)

[Aous Younis]

Thanks a lot

Answer 2

[Wayne King]

Looks to me like this just simplifies to:

\delta(t) +3\delta(t-1) + \delta(t-2)

N = 128;
 sig = zeros(N,1);
 idx = 1:3;
 sig(idx) = [1 3 1];
 stem(sig)

u(t)-u(t-1) is like the derivative of the unit step at t, which is the delta function (distribution)

You can see it's equal if you implement your equation above using the differences of the translated unit step functions:

   stepfunc = ones(128,4);
  stepfunc(1,2) = 0;
  stepfunc(1:2,3) = 0;
  stepfunc(1:3,4) = 0;

t = (0:127)';
v1 = 2*t+1;
v2 = -t+3;
v = v1.*(stepfunc(:,1)-stepfunc(:,2))+ 3*(stepfunc(:,2)-stepfunc(:,3))+...
v2.*(stepfunc(:,3)-stepfunc(:,4));
subplot(211)
stem(v)
subplot(212)
stem(sig)

[Azzi Abdelmalek]

From his post, the signal u seems to be continuous

[Aous Younis]

Thanks for ur help...but the signal is continuous