deriving surface equation form data on a table
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
i have a table with 3 variables(B/H)= 1,2,3,4,5,6,7,8 and fi= 0,10,20,30 and h which is depend on (B/H) and fi that contains 32 values. for example for fi=0 and (B/H)=1 >>h=1 fi=0 and (B/H)=2 >>h=1.02 ...... fi=30 and (B/H)=8 >>h=14800
>is there any way in MATLAB to get an surface equation for h in terms of (B/H) and fi??
h:[ 1 1.02 1.11 1.21 1.3 1.4 1.59 1.78
1 1.11 1.35 1.62 1.95 2.33 3.34 4.77
1.01 1.39 2.12 3.29 5.17 8.29 22 61
1.13 2.5 6.36 17.5 50 150 1400 14800 ]
4 Kommentare
Sean de Wolski
am 30 Jun. 2011
There can be at least one polynomial of order>(number elements) that fits perfectly. Thus from n-> infinity: To infinity and beyond!
Antworten (1)
Andrei Bobrov
am 30 Jun. 2011
BHv= [1,2,3,4,5,6,7,8];
fiv= [0,10,20,30];
h = rand(length(BHv),length(fiv))*30+10;
[fim BHm] = meshgrid(fiv,BHv);
[XI,YI] = meshgrid(linspace(fiv(1),fiv(end),100),linspace(BHv(1),BHv(end),100));
1 variant use 'interp2'
F1 = @(fi,BH)interp2(fim,BHm,h,fi,BH);
surf(F1(XI,YI))
2 variant use 'TriScatteredInterp'
F = TriScatteredInterp(fim(:),BHm(:),h(:));
figure,surf(F(XI,YI))
2 Kommentare
Siehe auch
Kategorien
Mehr zu Interpolation finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!