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Vectorization of matrices power

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Ubaldo Tiberi
Ubaldo Tiberi am 12 Nov. 2013
Bearbeitet: Matt J am 13 Nov. 2013
Hi all,
Let A a matrix n*n and let N an integer. I wish to create a matrix of power of the form AN = [I A A^2,...,A^N], where I=eye(n), without resorting to a "for" cycle. I have tried to take a look at several commands, including cumprod, kron, etc, and trying to combine them, but I failed. I made it only for the scalar case, i.e. n=1.
After that, I wish to create a matrix
AA = [I 0 0 0;A I 0 0;A^2 A I 0;A^3 A^2 A I]
without using any "for" cycle. I have noticed that the first column of AA is equal to AN' (if it may help). Any hints? Thanks.
  1 Kommentar
Matt J
Matt J am 12 Nov. 2013
It is doubtful that a for-loop is to be feared here. Surely you can't be doing this for N very large?

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Akzeptierte Antwort

Matt J
Matt J am 12 Nov. 2013
>> [AN,T]=matpowers(diag([2,3]),3),
AN =
1 0 2 0 4 0 8 0
0 1 0 3 0 9 0 27
T =
1 0 0 0 0 0 0 0
0 1 0 0 0 0 0 0
2 0 1 0 0 0 0 0
0 3 0 1 0 0 0 0
4 0 2 0 1 0 0 0
0 9 0 3 0 1 0 0
8 0 4 0 2 0 1 0
0 27 0 9 0 3 0 1
function [AN,T]=matpowers(A,c)
persistent pcell N
if isempty(pcell), pcell={eye(size(A))}; end
if nargin>1, N=c; end
if ~isempty(N) && N>0
pcell=[pcell,{pcell{end}*A}];
N=N-1;
AN=matpowers(A);
else
AN=pcell; pcell=[]; N=[];
end
if nargout>1
z=[AN,{zeros(size(A))}];
T=toeplitz(1:c+1,[1,ones(1,c)*(c+2)]);
T=cell2mat(z(T)) ;
AN=cell2mat(AN);
end

Weitere Antworten (2)

Sean de Wolski
Sean de Wolski am 12 Nov. 2013
This should give you the tools you need:
x = (1:3).^(1:3)
xm = tril(toeplitz(x))

Ubaldo Tiberi
Ubaldo Tiberi am 13 Nov. 2013
Thanks for the reply.
Sean, unfortunately it seems that your solution works only with scalar values and not for matrices.
Matt, thanks for the impressive answer! However, I was wondering if I can get the same result without using a function, but just by combining elementary Matlab operations such as blkdiag, kron, cumprod, etc. But I do like this function! However, how would you write a "for" cycle that solves my problem?
Thanks again!
  1 Kommentar
Matt J
Matt J am 13 Nov. 2013
Bearbeitet: Matt J am 13 Nov. 2013
but just by combining elementary Matlab operations such as blkdiag, kron, cumprod
If A is symmetric you might be able to. But I think a for-loop will be the most efficient, regardless. Are you sure you need to build these matrices explicitly? They contain a lot of redundant data. What are you planning to use them for?

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