Error using ==> mpower At least one operand must be scalar in mod operation
Ältere Kommentare anzeigen
hi all, i need ur little help here. i use this code
d=18;
n=19;
x=3;
d1=dec2bin(d);
r=1;
for i=1:length(d1)
r=mod((r^r),n);
if (d1(i)>=1)
r=r*(mod(x,n));
end
end
it's return this error: ??? Error using ==> mpower At least one operand must be scalar.
Error in ==> geje at 26
r=mod((r^r),n);
i don't know where is my mistake?? hope your solution
Antworten (4)
Paulo Silva
am 26 Jun. 2011
0 Stimmen
That code is working without any error and there's no line 26 in it
1 Kommentar
zikrullah muhammad
am 27 Jun. 2011
zikrullah muhammad
am 26 Jun. 2011
0 Stimmen
2 Kommentare
Paulo Silva
am 26 Jun. 2011
Run the code like this and see what appears on the command line
d=18;
n=19;
x=3;
d1=dec2bin(d);
r=1;
for i=1:length(d1)
r
n
r=mod((r^r),n)
if (d1(i)>=1)
r=r*(mod(x,n));
end
end
zikrullah muhammad
am 27 Jun. 2011
Matt Fig
am 26 Jun. 2011
0 Stimmen
There is more going on here than you say, because the code you pasted could not possibly have that error. The variable 'r' is a scalar going into the loop. Since 'x' and 'n' (both scalars) don't change in the loop, mod(x,n) is always 3. So the only way 'r' is changed, besides the line in question, is possibly by a factor of 3. A scalar multiplied by 3 is always a scalar, and so 'r' has no chance of not being a scalar. Since both operands passed to MPOWER are scalar, there can be no error.
Thus the code you show couldn't possibly have this error, assuming you haven't masked any built-in functions. So what have you left out of your post?
And by the way, please don't post new 'answers' when you are responding to an answer given by someone else. Instead, put a comment on their answer by clicking the "Comment on this Answer" link.
1 Kommentar
zikrullah muhammad
am 27 Jun. 2011
Walter Roberson
am 26 Jun. 2011
0 Stimmen
r^r is an error if r is not a scalar.
MATLAB knows how to raise a square matrix to a scalar power, and knows how to raise a scalar to a matrix power, but MATLAB cannot raise a matrix to a matrix power.
1 Kommentar
zikrullah muhammad
am 27 Jun. 2011
Kategorien
Mehr zu Startup and Shutdown finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!