Beantwortet
Accessing multiple fields in nested structures for string comparison
Assuming libinfo is a scalar structure, and hence libinfo.Raithinfo is a cell array, you may benefit from using cellfun (or arra...
Accessing multiple fields in nested structures for string comparison
Assuming libinfo is a scalar structure, and hence libinfo.Raithinfo is a cell array, you may benefit from using cellfun (or arra...
mehr als 8 Jahre vor | 1
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Beantwortet
How to create an array containing all possible combinations of 0's and 1's to length n
n = 3 c = arrayfun(@(k) mat2cell(dec2bin(0:2^k-1)-'0', ones(2^k,1), k), 1:n, 'un', 0) c = vertcat(c{:})
How to create an array containing all possible combinations of 0's and 1's to length n
n = 3 c = arrayfun(@(k) mat2cell(dec2bin(0:2^k-1)-'0', ones(2^k,1), k), 1:n, 'un', 0) c = vertcat(c{:})
mehr als 8 Jahre vor | 0
Beantwortet
Can I use unique to reduce one row, but keep reference to how many cells it was reduced from?
You are looking for some run-length encoding scheme: A = [ 1 1.5 2 2.5 3 3.5 4 4.5 5 10 10 10 20 20 3...
Can I use unique to reduce one row, but keep reference to how many cells it was reduced from?
You are looking for some run-length encoding scheme: A = [ 1 1.5 2 2.5 3 3.5 4 4.5 5 10 10 10 20 20 3...
mehr als 8 Jahre vor | 0
Gesendet
allcomb(varargin)
All combinations of input (v4.2, apr 2018)
mehr als 8 Jahre vor | 5 Downloads |
Gesendet
isfunction(FUN)
returns true for valid matlab functions (v3.2, apr 2018)
mehr als 8 Jahre vor | 2 Downloads |
Beantwortet
I try to optimalize a temperature when looking at different concentrations for a chemical reaction. I get a good plot for values of k from 1 tot 70 but when going higher it won't work anymore. I don't know what to do, anyone?
You should reset t(1) to zero before the inner loop. You might not even need a vector t. Just use t = t + tstep, as you only use...
I try to optimalize a temperature when looking at different concentrations for a chemical reaction. I get a good plot for values of k from 1 tot 70 but when going higher it won't work anymore. I don't know what to do, anyone?
You should reset t(1) to zero before the inner loop. You might not even need a vector t. Just use t = t + tstep, as you only use...
mehr als 8 Jahre vor | 0
Beantwortet
How does the for-cycle check its conditions?
You cannot change the parameters of the for-loop within the counter, as demonstrated here: a = 2 ; b = 6 ; c = 0 ; fo...
How does the for-cycle check its conditions?
You cannot change the parameters of the for-loop within the counter, as demonstrated here: a = 2 ; b = 6 ; c = 0 ; fo...
mehr als 8 Jahre vor | 1
Beantwortet
Find length of a structure element and remove them according to length?
L = arrayfun(@(k) numel(output(k).I), 1:numel(output)) output(L > 100) = [] ; % remove those elements of the structure arra...
Find length of a structure element and remove them according to length?
L = arrayfun(@(k) numel(output(k).I), 1:numel(output)) output(L > 100) = [] ; % remove those elements of the structure arra...
mehr als 8 Jahre vor | 1
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Beantwortet
I want to know the cell number i.e. row and column of the matrix, whichever is above 10% of the normal vlaue. and i also want to get the values in the cell.
I am unsure if I understand your question completely, but here is my 2p: X = rand(4,3) % example data TF = X > 0.1 ...
I want to know the cell number i.e. row and column of the matrix, whichever is above 10% of the normal vlaue. and i also want to get the values in the cell.
I am unsure if I understand your question completely, but here is my 2p: X = rand(4,3) % example data TF = X > 0.1 ...
mehr als 8 Jahre vor | 0
Beantwortet
Is it possible to do this without for cycle?
% data Y = [1 1 3 2 3 1 1 2] % M = numel(Y) K = 3 % engine T = double((Y(:) - (1:K))==0)
Is it possible to do this without for cycle?
% data Y = [1 1 3 2 3 1 1 2] % M = numel(Y) K = 3 % engine T = double((Y(:) - (1:K))==0)
mehr als 8 Jahre vor | 0
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Gesendet
nextperm(V, K)
Next (lexicographic) permutation of values
mehr als 8 Jahre vor | 2 Downloads |
Beantwortet
Add zeros to matrices same as length of another matrix
To pad an matrix A with zeros to match a larger or same-sized array B, you can use this: A = magic(3) B = ones(3, 5) ...
Add zeros to matrices same as length of another matrix
To pad an matrix A with zeros to match a larger or same-sized array B, you can use this: A = magic(3) B = ones(3, 5) ...
mehr als 8 Jahre vor | 0
Beantwortet
how do I convert a cell array of different size cells to a matrix
An easy job for padcat :) c = {{1 2}; {1 2 3};{4 5 6};{10 11 12 12 14}} % rather awkward cell array of cell arrays of n...
how do I convert a cell array of different size cells to a matrix
An easy job for padcat :) c = {{1 2}; {1 2 3};{4 5 6};{10 11 12 12 14}} % rather awkward cell array of cell arrays of n...
mehr als 8 Jahre vor | 0
Beantwortet
How to convert string to number and process underscores? (e.g. '57_77_' to 57.77)
all in one go: a = '12_23_' v = str2num(strrep(a(1:end-1), '_', '.'))
How to convert string to number and process underscores? (e.g. '57_77_' to 57.77)
all in one go: a = '12_23_' v = str2num(strrep(a(1:end-1), '_', '.'))
mehr als 8 Jahre vor | 1
Beantwortet
hi everybody , i'm a beginner and don't know how can i convert ascii to a string
A = [51 48 56 ; 73 48 71] str = char(A) % conversion from ascii to character string
hi everybody , i'm a beginner and don't know how can i convert ascii to a string
A = [51 48 56 ; 73 48 71] str = char(A) % conversion from ascii to character string
mehr als 8 Jahre vor | 0
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Beantwortet
find max value within set parameters of matrix
If you want to mask out elements of a vector for finding the max, without disrupting the location within the vector, you might c...
find max value within set parameters of matrix
If you want to mask out elements of a vector for finding the max, without disrupting the location within the vector, you might c...
mehr als 8 Jahre vor | 1
Beantwortet
Array indexing for moving IQR
When N (= number of elements in A) and K (= number of elements to use) are not too large you could create an intermediate (N-K+1...
Array indexing for moving IQR
When N (= number of elements in A) and K (= number of elements to use) are not too large you could create an intermediate (N-K+1...
mehr als 8 Jahre vor | 0
Beantwortet
Split a matrix at specific row
Use *mat2cell*: M = randi(20, 105,4) ; V = [11 12 11 11 12 12 13 11 12] ; C = mat2cell(M, V , size(M,2)) ;
Split a matrix at specific row
Use *mat2cell*: M = randi(20, 105,4) ; V = [11 12 11 11 12 12 13 11 12] ; C = mat2cell(M, V , size(M,2)) ;
mehr als 8 Jahre vor | 0
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Beantwortet
How to find minimal distance between elements?
Without creating a possibly large intermediate N-ny-N matrix or using a possibly slow sort V = [1 8 6 4 2 10] ; W = ncho...
How to find minimal distance between elements?
Without creating a possibly large intermediate N-ny-N matrix or using a possibly slow sort V = [1 8 6 4 2 10] ; W = ncho...
mehr als 8 Jahre vor | 2
Beantwortet
How to find minimal distance between elements?
By definition the minimum distance is zero because v(i)==v(i) for any element i of the vector v. But I assume you want the mi...
How to find minimal distance between elements?
By definition the minimum distance is zero because v(i)==v(i) for any element i of the vector v. But I assume you want the mi...
mehr als 8 Jahre vor | 0
Beantwortet
assign values from logial vector to a new matrix with the same size
function B = functionA(A) B = A B(~(A>0)) = 0
assign values from logial vector to a new matrix with the same size
function B = functionA(A) B = A B(~(A>0)) = 0
mehr als 8 Jahre vor | 0
Beantwortet
Compare segments of a vector
A = [2 2 2 2 2 3 6 3 4 5 1 1 1 1 1 2 3 4 5 6] AA = reshape(A,5,[]) dA = diff(AA,[],2) ix = all(dA>0) ix = 2*fin...
Compare segments of a vector
A = [2 2 2 2 2 3 6 3 4 5 1 1 1 1 1 2 3 4 5 6] AA = reshape(A,5,[]) dA = diff(AA,[],2) ix = all(dA>0) ix = 2*fin...
mehr als 8 Jahre vor | 0
Beantwortet
Structs fields indexing issue
Parent.Child1.field_1 = [1 2 2 3] ; Parent.Child2.field_1 = [1 3 3 2 3 2] ; Parent.Child3.field_1 = [2] ; A = str...
Structs fields indexing issue
Parent.Child1.field_1 = [1 2 2 3] ; Parent.Child2.field_1 = [1 3 3 2 3 2] ; Parent.Child3.field_1 = [2] ; A = str...
mehr als 8 Jahre vor | 0
Beantwortet
How to choose all other indices than ones I know?
Here are two options a = [11 12 13 14 15] i = [2 3] b1 = nan(size(a)) b1(i) = a(i) b2 = a i2 = setdi...
How to choose all other indices than ones I know?
Here are two options a = [11 12 13 14 15] i = [2 3] b1 = nan(size(a)) b1(i) = a(i) b2 = a i2 = setdi...
mehr als 8 Jahre vor | 1
Beantwortet
Average distance of nonzero diagonal to the main diagonal for sparse matrix
In your example, you do not need to check the diagonals at all, just the first row and column of the matrix! A = [0 5 0 1 ...
Average distance of nonzero diagonal to the main diagonal for sparse matrix
In your example, you do not need to check the diagonals at all, just the first row and column of the matrix! A = [0 5 0 1 ...
mehr als 8 Jahre vor | 0
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Beantwortet
Average distance of nonzero diagonal to the main diagonal for sparse matrix
Use the second argument of diag? A = sparse(cumsum(triu(ones(5)),2)) diag(A,1)
Average distance of nonzero diagonal to the main diagonal for sparse matrix
Use the second argument of diag? A = sparse(cumsum(triu(ones(5)),2)) diag(A,1)
mehr als 8 Jahre vor | 0
Beantwortet
How to Return two Matrix of dimension (T,N)
function [G, H] = MyInput(T,N) % do not name this function input, as this is already used by ML !!! G = zeros(T,N) ; % p...
How to Return two Matrix of dimension (T,N)
function [G, H] = MyInput(T,N) % do not name this function input, as this is already used by ML !!! G = zeros(T,N) ; % p...
mehr als 8 Jahre vor | 1
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Beantwortet
How to find sampling rate from a signal vector and a time vector?
The sampling rate is the number of samples collected per second. In most typical cases, this is (roughly) a fixed (single) value...
How to find sampling rate from a signal vector and a time vector?
The sampling rate is the number of samples collected per second. In most typical cases, this is (roughly) a fixed (single) value...
mehr als 8 Jahre vor | 3