Beantwortet
What does z(1) and z(2) mean in that context?
z(1) and z(2) mean the same as they would in any code - there is an expectation that z is an array with (at least) 2 values, oth...

fast 6 Jahre vor | 2

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Beantwortet
Index must be a positive integer less than or equal to the number of test sets.
selectBatch(k) is a cell array, which clearly is not an integer. selectBatch{k} may be what you want instead. That said, you...

fast 6 Jahre vor | 0

Beantwortet
check a condition once and remember it later in the code
Potentially you can change your if statement to the following, but it depends on what nu is as this does not seem to be defined ...

fast 6 Jahre vor | 1

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Beantwortet
Variable inside timer callback is lost after first iteration in GUI - undefined function or variable
This seems like the opposite problem to what I originally thought it was as I got distracted by the handles and assumed they wer...

fast 6 Jahre vor | 1

Beantwortet
Increase levels on colorbar
If you create the colourbar and keep its handle, e.g hColourbar = colorbar( hAxes ); then you can edit the properties of the c...

fast 6 Jahre vor | 0

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Frage


Working with 1d vector sequences
This is a problem I seem to come up against quite often in Matlab and have never really found a good solution to. Maybe there i...

fast 6 Jahre vor | 2 Antworten | 0

2

Antworten

Beantwortet
(Index in position 1 exceeds array bounds (must not exceed 1). error is popping up where it does not seem to apply
Well, I don't know about line 12, which (from counting - please indicate which is the line of the error message in future, it wo...

fast 6 Jahre vor | 0

Beantwortet
Store only 4 value from a loop
If you have a nested loop like that you would generally want something like x(t,i) = ... with a 2d output to match the 2 neste...

fast 6 Jahre vor | 0

Beantwortet
Detecting change in sign of values of a column
NewC = find( diff( sign( Data(:,2) ) ) ) + 1;

fast 6 Jahre vor | 1

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Beantwortet
How to reshape a matrix into nx2 matrix?
reshape( A( :, [ 1:2:end, 2:2:end ] ), [], 2 ) You may wish to change the final two arguments to the reshape command in diffe...

etwa 6 Jahre vor | 0

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Beantwortet
Unable to use a value of type cell as an index
You are passing in a variable called title to the second function. This will hide the function of the same name so that this in...

etwa 6 Jahre vor | 4

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Beantwortet
Assining fixed color for zero value
Define a colourmap of size n, assuming n is not huge, and then add black to the front of it n = 7; colourmap = [0 0 0; parula(...

etwa 6 Jahre vor | 0

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Beantwortet
Any way to use British spellings for function calls and arguments?
https://blogs.mathworks.com/loren/2016/04/01/the-queens-matlab/ I took this seriously at first and was appalled! Not because I...

etwa 6 Jahre vor | 2

Beantwortet
Matlab data classes advantages
https://uk.mathworks.com/help/matlab/matlab_prog/fundamental-matlab-classes.html In basic terms obviously floating point (doubl...

etwa 6 Jahre vor | 0

Beantwortet
How to concatenate 2 cell arrays containing strings?
vertcat( x{:} )

etwa 6 Jahre vor | 0

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Beantwortet
Why do I need to declare a variable inside a nested 'for' loop?
You are referring to it on the right-hand side of the equation as well as on the left. First time round it does not exist yet s...

etwa 6 Jahre vor | 1

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Beantwortet
signal processing (segmentation in time domain)
sig1 = sig( t >= 0.34 && t <= 4 ); sig2 = sig( t >= 6 && t <= 8.5 ); If you also need the t vector then apply it similarly. J...

etwa 6 Jahre vor | 0

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Beantwortet
finding inverse exponential value
If i and j are pixel values then you must have an image to which they are applied, e.g. im, in which case simply exp( -im(i,j) ...

etwa 6 Jahre vor | 0

Beantwortet
Reference to non-existent field error
exist('handles.mystructdata') does not work for struct fields. isfield( handles, 'mystructdata' ) is what you should use to c...

etwa 6 Jahre vor | 1

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Beantwortet
How to replace values of certain rows in a matrix?
a( [2 3], : ) = repmat( b, 2, 1 ) A bit more generally: indicesToReplace = [2 3]; a( [2 3], : ) = repmat( b, indicesToReplace...

etwa 6 Jahre vor | 0

Beantwortet
FFT step by step help
The lpad part is a little suspicious. If you have an odd length of signal it will not work as is. Apart from that though: xdf...

etwa 6 Jahre vor | 1

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Beantwortet
Index exceeds the number of array elements
[A, index] = unique (A); replaces what was in A with the result of unique (i.e. all the non-unique values removed) So indexing...

etwa 6 Jahre vor | 0

Beantwortet
Get position when using uicontextmenu
I use code like this to position my context menu under the cursor on an axes, though if you already have the figure handle at th...

etwa 6 Jahre vor | 0

Beantwortet
replace duplicate value by 0 in matrix or vector
[C,ia] = unique( b ); b( setdiff( 1:numel(b), ia ) ) = 0;

etwa 6 Jahre vor | 1

Beantwortet
Unrecognized function or variable 'axes34_CreateFcn'.
Unless you have explicitly created one axes don't have a createFcn set by default, so I assume you must have asked it to create ...

etwa 6 Jahre vor | 0

Beantwortet
disp function error in matlab coder
disp is not supported by Coder. sprintf should work though.

etwa 6 Jahre vor | 0

Beantwortet
How to create empty matrix in matlab?
myMatrix = cell( 10 ); would create a 10x10 cell array. If all your images are the same size though you'd be better off with t...

etwa 6 Jahre vor | 1

Beantwortet
How can I display a specific frame in my image series ?
image10 = allImages( :, :, 10 ); images2_5 = double( allImages( :, : [2 5] ) ); image2_minusImage5 = diff( images2_5, [], 3 );...

etwa 6 Jahre vor | 0

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Beantwortet
extract logical locations that match array
B .* A would seem to give what you want

etwa 6 Jahre vor | 0

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Beantwortet
how to select the desired range of each dimension from the 3d array?
new_precipitation = precipitation( 1400:1439, 500:519, 700:900 ) would create what you ask for though it will be 1 bigger in ea...

etwa 6 Jahre vor | 0

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