{"group":{"id":1,"name":"Community","lockable":false,"created_at":"2012-01-18T18:02:15.000Z","updated_at":"2025-12-14T01:33:56.000Z","description":"Problems submitted by members of the MATLAB Central community.","is_default":true,"created_by":161519,"badge_id":null,"featured":false,"trending":false,"solution_count_in_trending_period":0,"trending_last_calculated":"2025-12-14T00:00:00.000Z","image_id":null,"published":true,"community_created":false,"status_id":2,"is_default_group_for_player":false,"deleted_by":null,"deleted_at":null,"restored_by":null,"restored_at":null,"description_opc":null,"description_html":null,"published_at":null},"problems":[{"id":42932,"title":"If you have matrix A, create matrix B using matrix A as an \"element\"","description":" A =  [1     2     3     4;\r\n       5     6     7     8]\r\n B =  [1     2     3     4     1     2     3     4;\r\n       5     6     7     8     5     6     7     8;\r\n       1     2     3     4     1     2     3     4;\r\n       5     6     7     8     5     6     7     8]","description_html":"\u003cpre\u003e A =  [1     2     3     4;\r\n       5     6     7     8]\r\n B =  [1     2     3     4     1     2     3     4;\r\n       5     6     7     8     5     6     7     8;\r\n       1     2     3     4     1     2     3     4;\r\n       5     6     7     8     5     6     7     8]\u003c/pre\u003e","function_template":"function y = your_fcn_name(x)\r\n  y = x;\r\nend","test_suite":"%%\r\nx = [1 2 3 4;5 6 7 8];\r\nB_correct = [1 2 3 4 1 2 3 4;5 6 7 8 5 6 7 8;1 2 3 4 1 2 3 4;5 6 7 8 5 6 7 8];\r\nassert(isequal(your_fcn_name(x),B_correct))\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":0,"created_by":27348,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":129,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2016-08-26T20:23:48.000Z","updated_at":"2026-02-18T11:03:40.000Z","published_at":"2016-08-26T20:23:48.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ A =  [1     2     3     4;\\n       5     6     7     8]\\n B =  [1     2     3     4     1     2     3     4;\\n       5     6     7     8     5     6     7     8;\\n       1     2     3     4     1     2     3     4;\\n       5     6     7     8     5     6     7     8]]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":9,"title":"Who Has the Most Change?","description":"You have a matrix for which each row is a person and the columns represent the number of quarters, nickels, dimes, and pennies that person has (in that order). What is the row index of the person with the most money?\r\n\r\nNote for those unfamiliar with American coins: quarter = $0.25, dime = $0.10, nickel = $0.05, penny = $0.01.\r\n\r\nExample:\r\n \r\n Input  a = [1 0 0 0; 0 1 0 0]\r\n Output b = 1\r\n \r\nsince the first person will have $0.25 and the second person will have only $0.05.\r\n","description_html":"\u003cp\u003eYou have a matrix for which each row is a person and the columns represent the number of quarters, nickels, dimes, and pennies that person has (in that order). What is the row index of the person with the most money?\u003c/p\u003e\u003cp\u003eNote for those unfamiliar with American coins: quarter = $0.25, dime = $0.10, nickel = $0.05, penny = $0.01.\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre\u003e Input  a = [1 0 0 0; 0 1 0 0]\r\n Output b = 1\u003c/pre\u003e\u003cp\u003esince the first person will have $0.25 and the second person will have only $0.05.\u003c/p\u003e","function_template":"function b = most_change(a)\r\n  b = 1;\r\nend","test_suite":"%%\r\na = [1 2 1 15];\r\nb = 1;\r\nassert(isequal(most_change(a),b))\r\n\r\n%%\r\na = [ 1  2  1 15;\r\n      0  8  5  9];\r\nb = 2;\r\nassert(isequal(most_change(a),b))\r\n\r\n%%\r\na = [ 1 22  1 15;\r\n     12  3 13  7;\r\n     10  8 23 99];\r\nb = 3;\r\nassert(isequal(most_change(a),b))\r\n\r\n%%\r\na = [ 1 0 0 0; 0 0 0 24];\r\nb = 1;\r\nassert(isequal(most_change(a),b))\r\n\r\n\r\n%%\r\na = [ 0 1 2 1; 0 2 1 1];\r\nc = 1;\r\nassert(isequal(most_change(a),c))\r\n\r\n%% \r\n% There is a lot of confusion about this problem. Watch this.\r\na = [0 1 0 0; 0 0 1 0];\r\nc = 2;\r\nassert(isequal(most_change(a),c))\r\n% Now go back and read the problem description carefully.\r\n\r\n%%\r\na = [ 2 1 1 1; \r\n      1 2 1 1; \r\n      1 1 2 1; \r\n      1 1 1 2;\r\n      4 0 0 0];\r\nc = 5;\r\nassert(isequal(most_change(a),c))\r\n","published":true,"deleted":false,"likes_count":82,"comments_count":66,"created_by":1,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":9148,"test_suite_updated_at":"2012-02-15T19:44:10.000Z","rescore_all_solutions":false,"group_id":2,"created_at":"2012-01-18T01:00:18.000Z","updated_at":"2026-04-01T07:40:20.000Z","published_at":"2012-01-18T01:00:18.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYou have a matrix for which each row is a person and the columns represent the number of quarters, nickels, dimes, and pennies that person has (in that order). What is the row index of the person with the most money?\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eNote for those unfamiliar with American coins: quarter = $0.25, dime = $0.10, nickel = $0.05, penny = $0.01.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ Input  a = [1 0 0 0; 0 1 0 0]\\n Output b = 1]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003esince the first person will have $0.25 and the second person will have only $0.05.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"problem_search":{"errors":[],"problems":[{"id":42932,"title":"If you have matrix A, create matrix B using matrix A as an \"element\"","description":" A =  [1     2     3     4;\r\n       5     6     7     8]\r\n B =  [1     2     3     4     1     2     3     4;\r\n       5     6     7     8     5     6     7     8;\r\n       1     2     3     4     1     2     3     4;\r\n       5     6     7     8     5     6     7     8]","description_html":"\u003cpre\u003e A =  [1     2     3     4;\r\n       5     6     7     8]\r\n B =  [1     2     3     4     1     2     3     4;\r\n       5     6     7     8     5     6     7     8;\r\n       1     2     3     4     1     2     3     4;\r\n       5     6     7     8     5     6     7     8]\u003c/pre\u003e","function_template":"function y = your_fcn_name(x)\r\n  y = x;\r\nend","test_suite":"%%\r\nx = [1 2 3 4;5 6 7 8];\r\nB_correct = [1 2 3 4 1 2 3 4;5 6 7 8 5 6 7 8;1 2 3 4 1 2 3 4;5 6 7 8 5 6 7 8];\r\nassert(isequal(your_fcn_name(x),B_correct))\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":0,"created_by":27348,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":129,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2016-08-26T20:23:48.000Z","updated_at":"2026-02-18T11:03:40.000Z","published_at":"2016-08-26T20:23:48.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ A =  [1     2     3     4;\\n       5     6     7     8]\\n B =  [1     2     3     4     1     2     3     4;\\n       5     6     7     8     5     6     7     8;\\n       1     2     3     4     1     2     3     4;\\n       5     6     7     8     5     6     7     8]]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":9,"title":"Who Has the Most Change?","description":"You have a matrix for which each row is a person and the columns represent the number of quarters, nickels, dimes, and pennies that person has (in that order). What is the row index of the person with the most money?\r\n\r\nNote for those unfamiliar with American coins: quarter = $0.25, dime = $0.10, nickel = $0.05, penny = $0.01.\r\n\r\nExample:\r\n \r\n Input  a = [1 0 0 0; 0 1 0 0]\r\n Output b = 1\r\n \r\nsince the first person will have $0.25 and the second person will have only $0.05.\r\n","description_html":"\u003cp\u003eYou have a matrix for which each row is a person and the columns represent the number of quarters, nickels, dimes, and pennies that person has (in that order). What is the row index of the person with the most money?\u003c/p\u003e\u003cp\u003eNote for those unfamiliar with American coins: quarter = $0.25, dime = $0.10, nickel = $0.05, penny = $0.01.\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre\u003e Input  a = [1 0 0 0; 0 1 0 0]\r\n Output b = 1\u003c/pre\u003e\u003cp\u003esince the first person will have $0.25 and the second person will have only $0.05.\u003c/p\u003e","function_template":"function b = most_change(a)\r\n  b = 1;\r\nend","test_suite":"%%\r\na = [1 2 1 15];\r\nb = 1;\r\nassert(isequal(most_change(a),b))\r\n\r\n%%\r\na = [ 1  2  1 15;\r\n      0  8  5  9];\r\nb = 2;\r\nassert(isequal(most_change(a),b))\r\n\r\n%%\r\na = [ 1 22  1 15;\r\n     12  3 13  7;\r\n     10  8 23 99];\r\nb = 3;\r\nassert(isequal(most_change(a),b))\r\n\r\n%%\r\na = [ 1 0 0 0; 0 0 0 24];\r\nb = 1;\r\nassert(isequal(most_change(a),b))\r\n\r\n\r\n%%\r\na = [ 0 1 2 1; 0 2 1 1];\r\nc = 1;\r\nassert(isequal(most_change(a),c))\r\n\r\n%% \r\n% There is a lot of confusion about this problem. Watch this.\r\na = [0 1 0 0; 0 0 1 0];\r\nc = 2;\r\nassert(isequal(most_change(a),c))\r\n% Now go back and read the problem description carefully.\r\n\r\n%%\r\na = [ 2 1 1 1; \r\n      1 2 1 1; \r\n      1 1 2 1; \r\n      1 1 1 2;\r\n      4 0 0 0];\r\nc = 5;\r\nassert(isequal(most_change(a),c))\r\n","published":true,"deleted":false,"likes_count":82,"comments_count":66,"created_by":1,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":9148,"test_suite_updated_at":"2012-02-15T19:44:10.000Z","rescore_all_solutions":false,"group_id":2,"created_at":"2012-01-18T01:00:18.000Z","updated_at":"2026-04-01T07:40:20.000Z","published_at":"2012-01-18T01:00:18.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYou have a matrix for which each row is a person and the columns represent the number of quarters, nickels, dimes, and pennies that person has (in that order). What is the row index of the person with the most money?\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eNote for those unfamiliar with American coins: quarter = $0.25, dime = $0.10, nickel = $0.05, penny = $0.01.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ Input  a = [1 0 0 0; 0 1 0 0]\\n Output b = 1]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003esince the first person will have $0.25 and the second person will have only 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