{"group":{"id":1,"name":"Community","lockable":false,"created_at":"2012-01-18T18:02:15.000Z","updated_at":"2025-12-14T01:33:56.000Z","description":"Problems submitted by members of the MATLAB Central community.","is_default":true,"created_by":161519,"badge_id":null,"featured":false,"trending":false,"solution_count_in_trending_period":0,"trending_last_calculated":"2025-12-14T00:00:00.000Z","image_id":null,"published":true,"community_created":false,"status_id":2,"is_default_group_for_player":false,"deleted_by":null,"deleted_at":null,"restored_by":null,"restored_at":null,"description_opc":null,"description_html":null,"published_at":null},"problems":[{"id":8048,"title":"Stress-Strain Properties - 1","description":"This is the first in a series of problems regarding mechanics of materials, in particular, material properties drawn from stress-strain responses. A simplified typical stress-strain response is illustrated below (from quora.com):\r\n\r\nThe yield stress is the pressure required to start deformation of the material being tested. The yield point is the point along the response indicated by the yield stress (vertical axis) and the yield strain (horizontal axis). The response of the material up to this point is elastic, meaning that all deformation is reversible. The elastic modulus (E, also known as modulus of elasticity or Young's modulus) is the slope of this line. Write a function to calculate the elastic modulus for a material, provided the elastic strain and yield stress (yield point).\r\nNext problem: 2 - resilience.","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.440001px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none; white-space: normal; \"\u003e\u003cdiv style=\"block-size: 541px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 332px 270.5px; transform-origin: 332px 270.5px; vertical-align: baseline; \"\u003e\u003cdiv style=\"block-size: 63px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 31.5px; text-align: left; transform-origin: 309px 31.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eThis is the first in a series of problems regarding mechanics of materials, in particular, material properties drawn from stress-strain responses. A simplified typical stress-strain response is illustrated below (from\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e quora.com):\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 304px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 152px; text-align: center; transform-origin: 309px 152px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cimg class=\"imageNode\" style=\"vertical-align: baseline\" src=\"https://qph.cf2.quoracdn.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\" data-image-state=\"image-loaded\"\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 126px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 63px; text-align: left; transform-origin: 309px 63px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eThe yield stress is the pressure required to start deformation of the material being tested. The yield point is the point along the response indicated by the yield stress (vertical axis) and the yield strain (horizontal axis). The response of the material up to this point is elastic, meaning that all deformation is reversible. The elastic modulus (E, also known as modulus of elasticity or Young's modulus) is the slope of this line. Write a function to calculate the elastic modulus for a material, provided the elastic strain and yield stress (yield point).\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 21px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 10.5px; text-align: left; transform-origin: 309px 10.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eNext problem: 2 -\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e \u003c/span\u003e\u003c/span\u003e\u003ca target='_blank' href = \"https://www.mathworks.com/matlabcentral/cody/problems/8049-stress-strain-properties-2\"\u003e\u003cspan style=\"\"\u003e\u003cspan style=\"\"\u003eresilience\u003c/span\u003e\u003c/span\u003e\u003c/a\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003c/div\u003e\u003c/div\u003e","function_template":"function [E] = stress_strain1(S_y,e_y)\r\n\r\nE = 1;\r\n\r\nend\r\n","test_suite":"%% Note\r\n% The following properties are measured at room temperature and are tensile \r\n% in a single direction. Some materials, such as metals are generally\r\n% isotropic, whereas others, like composite are highly anisotropic\r\n% (different properties in different directions). Also, property values can\r\n% range depending on the material grade. Finally, thermal or environmental\r\n% changes can alter these properties, sometimes drastically.\r\n\r\n%% steel alloy (ASTM A36)\r\nS_y = 250e6; %Pa\r\nS_u = 400e6; %Pa\r\ne_y = 0.00125;\r\ne_u = 0.35;\r\nnu = 0.26;\r\nG = 79.3e9; %Pa\r\nE = 200e9; %Pa\r\ndensity = 7.85; %g/cm^3\r\nsh_exp = 0.14; %strain-hardening exponent\r\nsh_coeff = 0.463; %strain-hardening coefficient\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% titanium (Ti-6Al-4V)\r\nS_y = 830e6; %Pa\r\nS_u = 900e6; %Pa\r\ne_y = 0.00728;\r\ne_u = 0.14;\r\nnu = 0.342;\r\nG = 44e9; %Pa\r\nE = 114e9; %Pa\r\ndensity = 4.51; %g/cm^3\r\nsh_exp = 0.04; %strain-hardening exponent\r\nsh_coeff = 0.974; %strain-hardening coefficient\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% Inconel 718\r\nS_y = 1172e6; %Pa\r\nS_u = 1407e6; %Pa\r\ne_y = 0.00563;\r\ne_u = 0.027;\r\nnu = 0.29;\r\nG = 11.6e9; %Pa\r\nE = 208e9; %Pa\r\ndensity = 8.19; %g/cm^3\r\nsh_exp = 0.075; %strain-hardening exponent\r\nsh_coeff = 1.845; %strain-hardening coefficient\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% aluminum alloy (6061-T6)%^\u0026\r\nS_y = 241e6; %Pa\r\nS_u = 300e6; %Pa\r\ne_y = 0.0035;\r\ne_u = 0.15;\r\nnu = 0.33;\r\nG = 26e9; %Pa\r\nE = 68.9e9; %Pa\r\ndensity = 2.7; %g/cm^3\r\nsh_exp = 0.042; %strain-hardening exponent\r\nsh_coeff = 0.325; %strain-hardening coefficient\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% copper\r\nS_y = 70e6; %Pa\r\nS_u = 220e6; %Pa\r\ne_y = 0.00054;\r\ne_u = 0.48;\r\nnu = 0.34;\r\nG = 48e9; %Pa\r\nE = 130e9; %Pa\r\ndensity = 8.92; %g/cm^3\r\nsh_exp = 0.44; %strain-hardening exponent\r\nsh_coeff = 0.304; %strain-hardening coefficient 530MPa\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% rhenium\r\nS_y = 317e6; %Pa\r\nS_u = 1130e6; %Pa\r\ne_y = 0.000685;\r\ne_u = 0.24;\r\nnu = 0.3;\r\nG = 178e9; %Pa\r\nE = 463e9; %Pa\r\ndensity = 21.02; %g/cm^3\r\nsh_exp = 0.353; %strain-hardening exponent\r\nsh_coeff = 1.870; %strain-hardening coefficient\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% polymer (nylon, 6/6)\r\nS_y = 82e6; %Pa\r\nS_u = 82e6; %Pa\r\ne_y = 0.0265;\r\ne_u = 0.45;\r\nnu = 0.41;\r\nG = 2.8e9; %Pa\r\nE = 3.1e9; %Pa\r\ndensity = 1.14; %g/cm^3\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% polymer (nylon, 6/6) reinforced with 45wt.% glass fiber\r\nS_y = 230e6; %Pa\r\nS_u = 230e6; %Pa\r\ne_y = 0.016;\r\ne_u = 0.016;\r\nnu = 0.35;\r\nG = 13.0e9; %Pa\r\nE = 14.5e9; %Pa\r\ndensity = 1.51; %g/cm^3\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% diamond\r\nS_y = 1200e6; %Pa\r\nS_u = 1200e6; %Pa\r\ne_y = 0.001;\r\ne_u = 0.001;\r\nnu = 0.20;\r\nG = 478e9; %Pa\r\nE = 1200e9; %Pa\r\ndensity = 3.51; %g/cm^3\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":3,"created_by":26769,"edited_by":26769,"edited_at":"2024-03-27T17:40:39.000Z","deleted_by":null,"deleted_at":null,"solvers_count":324,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2015-03-30T18:09:31.000Z","updated_at":"2026-03-31T10:50:52.000Z","published_at":"2015-03-30T18:09:58.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThis is the first in a series of problems regarding mechanics of materials, in particular, material properties drawn from stress-strain responses. A simplified typical stress-strain response is illustrated below (from\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e quora.com):\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"center\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"verticalAlign\\\" w:val=\\\"baseline\\\"/\u003e\u003cw:attr w:name=\\\"altText\\\" w:val=\\\"\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId1\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe yield stress is the pressure required to start deformation of the material being tested. The yield point is the point along the response indicated by the yield stress (vertical axis) and the yield strain (horizontal axis). The response of the material up to this point is elastic, meaning that all deformation is reversible. The elastic modulus (E, also known as modulus of elasticity or Young's modulus) is the slope of this line. Write a function to calculate the elastic modulus for a material, provided the elastic strain and yield stress (yield point).\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eNext problem: 2 -\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"https://www.mathworks.com/matlabcentral/cody/problems/8049-stress-strain-properties-2\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eresilience\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\",\"relationship\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/image\",\"target\":\"/media/image1.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"relationshipId\":\"rId1\"}]},{\"partUri\":\"/media/image1.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"contentType\":\"image/net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"content\":\"https://qph.cf2.quoracdn.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"relationship\":null}],\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"target\":\"/matlab/document.xml\",\"relationshipId\":\"rId1\"}]}"},{"id":8052,"title":"Stress-Strain Properties - 5","description":"Similar to the previous problem, materials may be characterized by their stiffness-to-weight ratio, which is the elastic modulus divided by density. Write a function to calculate this ratio for a material provided its elastic modulus and density.\r\n\r\nPrevious problem: 4 - \u003chttp://www.mathworks.com/matlabcentral/cody/problems/8051-stress-strain-properties-4 strength-to-weight ratio\u003e. Next problem: 6 - \u003chttp://www.mathworks.com/matlabcentral/cody/problems/8053-stress-strain-properties-6 absorbed strain energy\u003e.","description_html":"\u003cp\u003eSimilar to the previous problem, materials may be characterized by their stiffness-to-weight ratio, which is the elastic modulus divided by density. Write a function to calculate this ratio for a material provided its elastic modulus and density.\u003c/p\u003e\u003cp\u003ePrevious problem: 4 - \u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/8051-stress-strain-properties-4\"\u003estrength-to-weight ratio\u003c/a\u003e. Next problem: 6 - \u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/8053-stress-strain-properties-6\"\u003eabsorbed strain energy\u003c/a\u003e.\u003c/p\u003e","function_template":"function [EtWR] = stress_strain5(E,density)\r\n\r\nEtWR = 1\r\n\r\nend\r\n","test_suite":"%% Note\r\n% The following properties are measured at room temperature and are tensile\r\n% in a single direction. Some materials, such as metals are generally\r\n% isotropic, whereas others, like composite are highly anisotropic\r\n% (different properties in different directions). Also, property values can\r\n% range depending on the material grade. Finally, thermal or environmental\r\n% changes can alter these properties, sometimes drastically.\r\n\r\n%% steel alloy (ASTM A36)\r\nS_y = 250e6; %Pa\r\nS_u = 400e6; %Pa\r\ne_y = 0.00125;\r\ne_u = 0.35;\r\nnu = 0.26;\r\nG = 79.3e9; %Pa\r\nE = 200e9; %Pa\r\ndensity = 7.85; %g/cm^3\r\nsh_exp = 0.14; %strain-hardening exponent\r\nsh_coeff = 0.463; %strain-hardening coefficient\r\nEtWR_corr = 2.548e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% titanium (Ti-6Al-4V)\r\nS_y = 830e6; %Pa\r\nS_u = 900e6; %Pa\r\ne_y = 0.00728;\r\ne_u = 0.14;\r\nnu = 0.342;\r\nG = 44e9; %Pa\r\nE = 114e9; %Pa\r\ndensity = 4.51; %g/cm^3\r\nsh_exp = 0.04; %strain-hardening exponent\r\nsh_coeff = 0.974; %strain-hardening coefficient\r\nEtWR_corr = 2.528e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% Inconel 718\r\nS_y = 1172e6; %Pa\r\nS_u = 1407e6; %Pa\r\ne_y = 0.00563;\r\ne_u = 0.027;\r\nnu = 0.29;\r\nG = 11.6e9; %Pa\r\nE = 208e9; %Pa\r\ndensity = 8.19; %g/cm^3\r\nsh_exp = 0.075; %strain-hardening exponent\r\nsh_coeff = 1.845; %strain-hardening coefficient\r\nEtWR_corr = 2.540e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% aluminum alloy (6061-T6)%^\u0026\r\nS_y = 241e6; %Pa\r\nS_u = 300e6; %Pa\r\ne_y = 0.0035;\r\ne_u = 0.15;\r\nnu = 0.33;\r\nG = 26e9; %Pa\r\nE = 68.9e9; %Pa\r\ndensity = 2.7; %g/cm^3\r\nsh_exp = 0.042; %strain-hardening exponent\r\nsh_coeff = 0.325; %strain-hardening coefficient\r\nEtWR_corr = 2.552e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% copper\r\nS_y = 70e6; %Pa\r\nS_u = 220e6; %Pa\r\ne_y = 0.00054;\r\ne_u = 0.48;\r\nnu = 0.34;\r\nG = 48e9; %Pa\r\nE = 130e9; %Pa\r\ndensity = 8.92; %g/cm^3\r\nsh_exp = 0.44; %strain-hardening exponent\r\nsh_coeff = 0.304; %strain-hardening coefficient\r\nEtWR_corr = 1.457e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% rhenium\r\nS_y = 317e6; %Pa\r\nS_u = 1130e6; %Pa\r\ne_y = 0.000685;\r\ne_u = 0.24;\r\nnu = 0.3;\r\nG = 178e9; %Pa\r\nE = 463e9; %Pa\r\ndensity = 21.02; %g/cm^3\r\nsh_exp = 0.353; %strain-hardening exponent\r\nsh_coeff = 1.870; %strain-hardening coefficient\r\nEtWR_corr = 2.203e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% polymer (nylon, 6/6)\r\nS_y = 82e6; %Pa\r\nS_u = 82e6; %Pa\r\ne_y = 0.0265;\r\ne_u = 0.45;\r\nnu = 0.41;\r\nG = 2.8e9; %Pa\r\nE = 3.1e9; %Pa\r\ndensity = 1.14; %g/cm^3\r\nEtWR_corr = 0.272e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% polymer (nylon, 6/6) reinforced with 45wt.% glass fiber\r\nS_y = 230e6; %Pa\r\nS_u = 230e6; %Pa\r\ne_y = 0.016;\r\ne_u = 0.016;\r\nnu = 0.35;\r\nG = 13.0e9; %Pa\r\nE = 14.5e9; %Pa\r\ndensity = 1.51; %g/cm^3\r\nEtWR_corr = 0.960e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% diamond\r\nS_y = 1200e6; %Pa\r\nS_u = 1200e6; %Pa\r\ne_y = 0.001;\r\ne_u = 0.001;\r\nnu = 0.20;\r\nG = 478e9; %Pa\r\nE = 1200e9; %Pa\r\ndensity = 3.51; %g/cm^3\r\nEtWR_corr = 34.19e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%%\r\nind = randi(4);\r\nswitch ind\r\n\tcase 1\r\n\t\tE = 114e9; %Pa\r\n\t\tdensity = 4.51; %g/cm^3\r\n\t\tEtWR_corr = 2.528e10;\r\n\tcase 2\r\n\t\tE = 68.9e9; %Pa\r\n\t\tdensity = 2.7; %g/cm^3\r\n\t\tEtWR_corr = 2.552e10;\r\n\tcase 3\r\n\t\tE = 200e9; %Pa\r\n\t\tdensity = 7.85; %g/cm^3\r\n\t\tEtWR_corr = 2.548e10;\r\n\tcase 4\r\n\t\tE = 1200e9; %Pa\r\n\t\tdensity = 3.51; %g/cm^3\r\n\t\tEtWR_corr = 34.19e10;\r\nend\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%%\r\nind = randi(4);\r\nswitch ind\r\n\tcase 1\r\n\t\tE = 68.9e9; %Pa\r\n\t\tdensity = 2.7; %g/cm^3\r\n\t\tEtWR_corr = 2.552e10;\r\n\tcase 2\r\n\t\tE = 3.1e9; %Pa\r\n\t\tdensity = 1.14; %g/cm^3\r\n\t\tEtWR_corr = 0.272e10;\r\n\tcase 3\r\n\t\tE = 14.5e9; %Pa\r\n\t\tdensity = 1.51; %g/cm^3\r\n\t\tEtWR_corr = 0.960e10;\r\n\tcase 4\r\n\t\tE = 208e9; %Pa\r\n\t\tdensity = 8.19; %g/cm^3\r\n\t\tEtWR_corr = 2.540e10;\r\nend\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%%\r\nind = randi(4);\r\nswitch ind\r\n\tcase 1\r\n\t\tE = 208e9; %Pa\r\n\t\tdensity = 8.19; %g/cm^3\r\n\t\tEtWR_corr = 2.540e10;\r\n\tcase 2\r\n\t\tE = 463e9; %Pa\r\n\t\tdensity = 21.02; %g/cm^3\r\n\t\tEtWR_corr = 2.203e10;\r\n\tcase 3\r\n\t\tE = 130e9; %Pa\r\n\t\tdensity = 8.92; %g/cm^3\r\n\t\tEtWR_corr = 1.457e10;\r\n\tcase 4\r\n\t\tE = 3.1e9; %Pa\r\n\t\tdensity = 1.14; %g/cm^3\r\n\t\tEtWR_corr = 0.272e10;\r\nend\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":26769,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":212,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2015-03-30T19:40:12.000Z","updated_at":"2026-03-10T20:42:38.000Z","published_at":"2015-03-30T19:40:12.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eSimilar to the previous problem, materials may be characterized by their stiffness-to-weight ratio, which is the elastic modulus divided by density. Write a function to calculate this ratio for a material provided its elastic modulus and density.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ePrevious problem: 4 -\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/8051-stress-strain-properties-4\\\"\u003e\u003cw:r\u003e\u003cw:t\u003estrength-to-weight ratio\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e. Next problem: 6 -\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/8053-stress-strain-properties-6\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eabsorbed strain energy\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":8049,"title":"Stress-Strain Properties - 2","description":"The resilience of a material is its ability to resist permanent (or plastic) deformation. The resilience coincides with the elastic region in the figure below and is calculated as the area under the stress-strain curve up to the yield point. Given that the elastic region is presumed to be entirely linear, this area is a triangle. Write a function to calculate the resilience of a material provided its elastic strain and yield stress (yield strength).\r\n\r\n(from quora.com)\r\nPrevious problem: 1 - elastic modulus. Next problem: 3 - qualitative measure of brittleness.","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.440001px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none; white-space: normal; \"\u003e\u003cdiv style=\"block-size: 478px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 332px 239px; transform-origin: 332px 239px; vertical-align: baseline; \"\u003e\u003cdiv style=\"block-size: 105px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 52.5px; text-align: left; transform-origin: 309px 52.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eThe resilience of a material is its ability to resist permanent (or plastic) deformation. The resilience coincides with the elastic region in the figure below and is calculated as the area under the stress-strain curve up to the yield point. Given that the elastic region is presumed to be entirely linear, this area is a triangle. Write a function to calculate the resilience of a material provided its elastic strain and yield stress (yield strength).\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 304px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 152px; text-align: center; transform-origin: 309px 152px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cimg class=\"imageNode\" style=\"vertical-align: baseline\" src=\"https://qph.cf2.quoracdn.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\" data-image-state=\"image-loaded\"\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 21px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 10.5px; text-align: center; transform-origin: 309px 10.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e(from quora.com)\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 21px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 10.5px; text-align: left; transform-origin: 309px 10.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003ePrevious problem: 1 - \u003c/span\u003e\u003c/span\u003e\u003ca target='_blank' href = \"https://www.mathworks.com/matlabcentral/cody/problems/8048-stress-strain-properties-1\"\u003e\u003cspan style=\"\"\u003e\u003cspan style=\"\"\u003eelastic modulus\u003c/span\u003e\u003c/span\u003e\u003c/a\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e. Next problem: 3 -\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e \u003c/span\u003e\u003c/span\u003e\u003ca target='_blank' href = \"/#null\"\u003e\u003cspan style=\"\"\u003e\u003cspan style=\"\"\u003equalitative measure of brittleness\u003c/span\u003e\u003c/span\u003e\u003c/a\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003c/div\u003e\u003c/div\u003e","function_template":"function [R] = stress_strain2(S_y,e_y)\r\n\r\nR = 1;\r\n\r\nend\r\n","test_suite":"%% Note\r\n% The following properties are measured at room temperature and are tensile\r\n% in a single direction. Some materials, such as metals are generally\r\n% isotropic, whereas others, like composite are highly anisotropic\r\n% (different properties in different directions). Also, property values can\r\n% range depending on the material grade. Finally, thermal or environmental\r\n% changes can alter these properties, sometimes drastically.\r\n\r\n%% steel alloy (ASTM A36)\r\nS_y = 250e6; %Pa\r\nS_u = 400e6; %Pa\r\ne_y = 0.00125;\r\ne_u = 0.35;\r\nnu = 0.26;\r\nG = 79.3e9; %Pa\r\nE = 200e9; %Pa\r\ndensity = 7.85; %g/cm^3\r\nsh_exp = 0.14; %strain-hardening exponent\r\nsh_coeff = 0.463; %strain-hardening coefficient\r\nassert(abs(stress_strain2(S_y,e_y)-1.5625e5)/1.5625e5\u003c5e-2)\r\n\r\n%% titanium (Ti-6Al-4V)\r\nS_y = 830e6; %Pa\r\nS_u = 900e6; %Pa\r\ne_y = 0.00728;\r\ne_u = 0.14;\r\nnu = 0.342;\r\nG = 44e9; %Pa\r\nE = 114e9; %Pa\r\ndensity = 4.51; %g/cm^3\r\nsh_exp = 0.04; %strain-hardening exponent\r\nsh_coeff = 0.974; %strain-hardening coefficient\r\nassert(abs(stress_strain2(S_y,e_y)-3.0212e6)/3.0212e6\u003c5e-2)\r\n\r\n%% Inconel 718\r\nS_y = 1172e6; %Pa\r\nS_u = 1407e6; %Pa\r\ne_y = 0.00563;\r\ne_u = 0.027;\r\nnu = 0.29;\r\nG = 11.6e9; %Pa\r\nE = 208e9; %Pa\r\ndensity = 8.19; %g/cm^3\r\nsh_exp = 0.075; %strain-hardening exponent\r\nsh_coeff = 1.845; %strain-hardening coefficient\r\nassert(abs(stress_strain2(S_y,e_y)-3.29918e6)/3.29918e6\u003c5e-2)\r\n\r\n%% aluminum alloy (6061-T6)%^\u0026\r\nS_y = 241e6; %Pa\r\nS_u = 300e6; %Pa\r\ne_y = 0.0035;\r\ne_u = 0.15;\r\nnu = 0.33;\r\nG = 26e9; %Pa\r\nE = 68.9e9; %Pa\r\ndensity = 2.7; %g/cm^3\r\nsh_exp = 0.042; %strain-hardening exponent\r\nsh_coeff = 0.325; %strain-hardening coefficient\r\nassert(abs(stress_strain2(S_y,e_y)-4.2175e5)/4.2175e5\u003c5e-2)\r\n\r\n%% copper\r\nS_y = 70e6; %Pa\r\nS_u = 220e6; %Pa\r\ne_y = 0.00054;\r\ne_u = 0.48;\r\nnu = 0.34;\r\nG = 48e9; %Pa\r\nE = 130e9; %Pa\r\ndensity = 8.92; %g/cm^3\r\nsh_exp = 0.44; %strain-hardening exponent\r\nsh_coeff = 0.304; %strain-hardening coefficient 530MPa\r\nassert(abs(stress_strain2(S_y,e_y)-1.89e4)/1.89e4\u003c5e-2)\r\n\r\n%% rhenium\r\nS_y = 317e6; %Pa\r\nS_u = 1130e6; %Pa\r\ne_y = 0.000685;\r\ne_u = 0.24;\r\nnu = 0.3;\r\nG = 178e9; %Pa\r\nE = 463e9; %Pa\r\ndensity = 21.02; %g/cm^3\r\nsh_exp = 0.353; %strain-hardening exponent\r\nsh_coeff = 1.870; %strain-hardening coefficient\r\nassert(abs(stress_strain2(S_y,e_y)-1.085725e5)/1.085725e5\u003c5e-2)\r\n\r\n%% polymer (nylon, 6/6)\r\nS_y = 82e6; %Pa\r\nS_u = 82e6; %Pa\r\ne_y = 0.0265;\r\ne_u = 0.45;\r\nnu = 0.41;\r\nG = 2.8e9; %Pa\r\nE = 3.5e-2; %Pa\r\ndensity = 1.14; %g/cm^3\r\nassert(abs(stress_strain2(S_y,e_y)-1.0865e6)/1.0865e6\u003c5e-2)\r\n\r\n%% polymer (nylon, 6/6) reinforced with 45wt.% glass fiber\r\nS_y = 230e6; %Pa\r\nS_u = 230e6; %Pa\r\ne_y = 0.016;\r\ne_u = 0.016;\r\nnu = 0.35;\r\nG = 13.0e9; %Pa\r\nE = 14.5e9; %Pa\r\ndensity = 1.51; %g/cm^3\r\nassert(abs(stress_strain2(S_y,e_y)-1.84e6)/1.84e6\u003c5e-2)\r\n\r\n%% diamond\r\nS_y = 1200e6; %Pa\r\nS_u = 1200e6; %Pa\r\ne_y = 0.001;\r\ne_u = 0.001;\r\nnu = 0.20;\r\nG = 478e9; %Pa\r\nE = 1200e9; %Pa\r\ndensity = 3.51; %g/cm^3\r\nassert(abs(stress_strain2(S_y,e_y)-6e5)/6e5\u003c5e-2)\r\n\r\n%%\r\nind = randi(4);\r\nswitch ind\r\n\tcase 1\r\n\t\tS_y = 250e6; %Pa\r\n\t\te_y = 0.00125;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.5625e5)/1.5625e5\u003c5e-2)\r\n\tcase 2\r\n\t\tS_y = 82e6; %Pa\r\n\t\te_y = 0.0265;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.0865e6)/1.0865e6\u003c5e-2)\r\n\tcase 3\r\n\t\tS_y = 241e6; %Pa\r\n\t\te_y = 0.0035;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-4.2175e5)/4.2175e5\u003c5e-2)\r\n\tcase 4\r\n\t\tS_y = 1172e6; %Pa\r\n\t\te_y = 0.00563;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-3.29918e6)/3.29918e6\u003c5e-2)\r\nend\r\n\r\n%%\r\nind = randi(4);\r\nswitch ind\r\n\tcase 1\r\n\t\tS_y = 1200e6; %Pa\r\n\t\te_y = 0.001;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-6e5)/6e5\u003c5e-2)\r\n\tcase 2\r\n\t\tS_y = 1172e6; %Pa\r\n\t\te_y = 0.00563;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-3.29918e6)/3.29918e6\u003c5e-2)\r\n\tcase 3\r\n\t\tS_y = 230e6; %Pa\r\n\t\te_y = 0.016;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.84e6)/1.84e6\u003c5e-2)\r\n\tcase 4\r\n\t\tS_y = 250e6; %Pa\r\n\t\te_y = 0.00125;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.5625e5)/1.5625e5\u003c5e-2)\r\nend\r\n\r\n%%\r\nind = randi(4);\r\nswitch ind\r\n\tcase 1\r\n\t\tS_y = 830e6; %Pa\r\n\t\te_y = 0.00728;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-3.0212e6)/3.0212e6\u003c5e-2)\r\n\tcase 2\r\n\t\tS_y = 230e6; %Pa\r\n\t\te_y = 0.016;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.84e6)/1.84e6\u003c5e-2)\r\n\tcase 3\r\n\t\tS_y = 70e6; %Pa\r\n\t\te_y = 0.00054;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.89e4)/1.89e4\u003c5e-2)\r\n\tcase 4\r\n\t\tS_y = 317e6; %Pa\r\n\t\te_y = 0.000685;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.085725e5)/1.085725e5\u003c5e-2)\r\nend\r\n","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":26769,"edited_by":26769,"edited_at":"2024-03-27T17:41:09.000Z","deleted_by":null,"deleted_at":null,"solvers_count":264,"test_suite_updated_at":"2015-03-30T18:44:33.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2015-03-30T18:27:49.000Z","updated_at":"2026-03-31T10:53:49.000Z","published_at":"2015-03-30T18:27:49.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe resilience of a material is its ability to resist permanent (or plastic) deformation. The resilience coincides with the elastic region in the figure below and is calculated as the area under the stress-strain curve up to the yield point. Given that the elastic region is presumed to be entirely linear, this area is a triangle. Write a function to calculate the resilience of a material provided its elastic strain and yield stress (yield strength).\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"center\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"verticalAlign\\\" w:val=\\\"baseline\\\"/\u003e\u003cw:attr w:name=\\\"altText\\\" w:val=\\\"\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId1\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"center\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e(from quora.com)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ePrevious problem: 1 - \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"https://www.mathworks.com/matlabcentral/cody/problems/8048-stress-strain-properties-1\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eelastic modulus\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e. Next problem: 3 -\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"\\\"\u003e\u003cw:r\u003e\u003cw:t\u003equalitative measure of brittleness\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\",\"relationship\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/image\",\"target\":\"/media/image1.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"relationshipId\":\"rId1\"}]},{\"partUri\":\"/media/image1.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"contentType\":\"image/net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"content\":\"https://qph.cf2.quoracdn.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"relationship\":null}],\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"target\":\"/matlab/document.xml\",\"relationshipId\":\"rId1\"}]}"},{"id":8055,"title":"Stress-Strain Properties - 8","description":"Up to this point, you've calculated some material properties based on tensile stress-strain data. For this problem, you are tasked with writing a function to calculate all of these properties and gather them, along with supplied properties, such as strain values, into an array. You'll be provided a cell array of strings in the function template; you must return an accompanying numerical array that contains all the specified properties. Below is the list of properties for a material, both supplied and calculated, that make up the array (with variable names that have been used):\r\n\r\n* Yield Strength (S_y)\r\n* Yield Strain (e_y)\r\n* Ultimate Strength (S_u)\r\n* Failure Strain (e_u)\r\n* Poisson's Ratio (nu)\r\n* Shear Modulus (G)\r\n* Elastic Modulus (E)\r\n* Density\r\n* Strain-hardening Exponent (sh_exp)\r\n* Strain-hardening Coefficient (sh_coeff)\r\n* Resilience (R)\r\n* Strength-to-weight Ratio (StWR)\r\n* Stiffness-to-weight Ratio (EtWR)\r\n* Absorbed Strain Energy (ASE)\r\n* Toughness (T)\r\n\r\nPrevious problem: 7 - \u003chttp://www.mathworks.com/matlabcentral/cody/problems/8054-stress-strain-properties-7 toughness\u003e.","description_html":"\u003cp\u003eUp to this point, you've calculated some material properties based on tensile stress-strain data. For this problem, you are tasked with writing a function to calculate all of these properties and gather them, along with supplied properties, such as strain values, into an array. You'll be provided a cell array of strings in the function template; you must return an accompanying numerical array that contains all the specified properties. Below is the list of properties for a material, both supplied and calculated, that make up the array (with variable names that have been used):\u003c/p\u003e\u003cul\u003e\u003cli\u003eYield Strength (S_y)\u003c/li\u003e\u003cli\u003eYield Strain (e_y)\u003c/li\u003e\u003cli\u003eUltimate Strength (S_u)\u003c/li\u003e\u003cli\u003eFailure Strain (e_u)\u003c/li\u003e\u003cli\u003ePoisson's Ratio (nu)\u003c/li\u003e\u003cli\u003eShear Modulus (G)\u003c/li\u003e\u003cli\u003eElastic Modulus (E)\u003c/li\u003e\u003cli\u003eDensity\u003c/li\u003e\u003cli\u003eStrain-hardening Exponent (sh_exp)\u003c/li\u003e\u003cli\u003eStrain-hardening Coefficient (sh_coeff)\u003c/li\u003e\u003cli\u003eResilience (R)\u003c/li\u003e\u003cli\u003eStrength-to-weight Ratio (StWR)\u003c/li\u003e\u003cli\u003eStiffness-to-weight Ratio (EtWR)\u003c/li\u003e\u003cli\u003eAbsorbed Strain Energy (ASE)\u003c/li\u003e\u003cli\u003eToughness (T)\u003c/li\u003e\u003c/ul\u003e\u003cp\u003ePrevious problem: 7 - \u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/8054-stress-strain-properties-7\"\u003etoughness\u003c/a\u003e.\u003c/p\u003e","function_template":"function [arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff)\r\n\r\narr_descr = {\r\n\t'Yield Strength','Yield Strain','Ultimate Strength','Failure Strain',...\r\n\t'Poisson''s Ratio','Shear Modulus','Elastic Modulus','Density',...\r\n\t'Strain-hardening Exponent','Strain-hardening Coefficient',...\r\n\t'Resilience','Strength-to-weight Ratio','Stiffness-to-weight Ratio',...\r\n\t'Absorbed Strain Energy','Toughness';\r\n};\r\n\r\narr_vals = [\r\n\t1;\r\n];\r\n\r\nend\r\n","test_suite":"%% Note\r\n% The following properties are measured at room temperature and are tensile\r\n% in a single direction. Some materials, such as metals are generally\r\n% isotropic, whereas others, like composite are highly anisotropic\r\n% (different properties in different directions). Also, property values can\r\n% range depending on the material grade. Finally, thermal or environmental\r\n% changes can alter these properties, sometimes drastically.\r\n\r\n%% steel alloy (ASTM A36)\r\nS_y = 250e6; %Pa\r\nS_u = 400e6; %Pa\r\ne_y = 0.00125;\r\ne_u = 0.35;\r\nnu = 0.26; %Poisson's ratio\r\nG = 79.3e9; %Pa (shear modulus)\r\nE = 200e9; %Pa  (elastic modulus)\r\ndensity = 7.85; %g/cm^3\r\nsh_exp = 0.14; %strain-hardening exponent\r\nsh_coeff = 463e6; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t1.5625e5, 5.096e7, 2.548e10, 12.28e7, 12.26e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% titanium (Ti-6Al-4V)\r\nS_y = 830e6; %Pa\r\nS_u = 900e6; %Pa\r\ne_y = 0.00728;\r\ne_u = 0.14;\r\nnu = 0.342;\r\nG = 44e9; %Pa\r\nE = 114e9; %Pa\r\ndensity = 4.51; %g/cm^3\r\nsh_exp = 0.04; %strain-hardening exponent\r\nsh_coeff = 974e6; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t3.0212e6, 19.96e7, 2.528e10, 12.12e7, 11.82e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% Inconel 718\r\nS_y = 1172e6; %Pa\r\nS_u = 1407e6; %Pa\r\ne_y = 0.00563;\r\ne_u = 0.027;\r\nnu = 0.29;\r\nG = 11.6e9; %Pa\r\nE = 208e9; %Pa\r\ndensity = 8.19; %g/cm^3\r\nsh_exp = 0.075; %strain-hardening exponent\r\nsh_coeff = 1845e6; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t3.29918e6, 17.18e7, 2.540e10, 3.535e7, 3.205e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% aluminum alloy (6061-T6)%^\u0026\r\nS_y = 241e6; %Pa\r\nS_u = 300e6; %Pa\r\ne_y = 0.0035;\r\ne_u = 0.15;\r\nnu = 0.33;\r\nG = 26e9; %Pa\r\nE = 68.9e9; %Pa\r\ndensity = 2.7; %g/cm^3\r\nsh_exp = 0.042; %strain-hardening exponent\r\nsh_coeff = 325e6; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t4.2175e5, 11.11e7, 2.552e10, 4.321e7, 4.279e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% copper\r\nS_y = 70e6; %Pa\r\nS_u = 220e6; %Pa\r\ne_y = 0.00054;\r\ne_u = 0.48;\r\nnu = 0.34;\r\nG = 48e9; %Pa\r\nE = 130e9; %Pa\r\ndensity = 8.92; %g/cm^3\r\nsh_exp = 0.44; %strain-hardening exponent\r\nsh_coeff = 304e6; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t1.89e4, 2.466e7, 1.457e10, 7.342e7, 7.340e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% rhenium\r\nS_y = 317e6; %Pa\r\nS_u = 1130e6; %Pa\r\ne_y = 0.000685;\r\ne_u = 0.24;\r\nnu = 0.3;\r\nG = 178e9; %Pa\r\nE = 463e9; %Pa\r\ndensity = 21.02; %g/cm^3\r\nsh_exp = 0.353; %strain-hardening exponent\r\nsh_coeff = 1870e6; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t1.085725e5, 5.376e7, 2.203e10, 20.06e7, 20.05e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% polymer (nylon, 6/6)\r\nS_y = 82e6; %Pa\r\nS_u = 82e6; %Pa\r\ne_y = 0.0265;\r\ne_u = 0.45;\r\nnu = 0.41;\r\nG = 2.8e9; %Pa\r\nE = 3.1e9; %Pa\r\ndensity = 1.14; %g/cm^3\r\nsh_exp = 0; %strain-hardening exponent\r\nsh_coeff = 0; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t1.0865e6, 7.193e7, 0.272e10, 3.581e7, 3.473e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\ndiffs(isnan(diffs)) = 0;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% polymer (nylon, 6/6) reinforced with 45wt.% glass fiber\r\nS_y = 230e6; %Pa\r\nS_u = 230e6; %Pa\r\ne_y = 0.016;\r\ne_u = 0.016;\r\nnu = 0.35;\r\nG = 13.0e9; %Pa\r\nE = 14.5e9; %Pa\r\ndensity = 1.51; %g/cm^3\r\nsh_exp = 0; %strain-hardening exponent\r\nsh_coeff = 0; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t1.84e6, 15.23e7, 0.960e10, 0.184e7, 0];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\ndiffs(isnan(diffs)) = 0;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% diamond\r\nS_y = 1200e6; %Pa\r\nS_u = 1200e6; %Pa\r\ne_y = 0.001;\r\ne_u = 0.001;\r\nnu = 0.20;\r\nG = 478e9; %Pa\r\nE = 1200e9; %Pa\r\ndensity = 3.51; %g/cm^3\r\nsh_exp = 0; %strain-hardening exponent\r\nsh_coeff = 0; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t6e5, 34.19e7, 34.19e10, 0.06e7, 0];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\ndiffs(isnan(diffs)) = 0;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n","published":true,"deleted":false,"likes_count":0,"comments_count":0,"created_by":26769,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":48,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2015-03-31T02:36:58.000Z","updated_at":"2026-02-19T09:49:12.000Z","published_at":"2015-03-31T02:36:58.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eUp to this point, you've calculated some material properties based on tensile stress-strain data. For this problem, you are tasked with writing a function to calculate all of these properties and gather them, along with supplied properties, such as strain values, into an array. You'll be provided a cell array of strings in the function template; you must return an accompanying numerical array that contains all the specified properties. Below is the list of properties for a material, both supplied and calculated, that make up the array (with variable names that have been used):\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYield Strength (S_y)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYield Strain (e_y)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eUltimate Strength (S_u)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFailure Strain (e_u)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ePoisson's Ratio (nu)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eShear Modulus (G)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eElastic Modulus (E)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eDensity\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eStrain-hardening Exponent (sh_exp)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eStrain-hardening Coefficient (sh_coeff)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eResilience (R)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eStrength-to-weight Ratio (StWR)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eStiffness-to-weight Ratio (EtWR)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eAbsorbed Strain Energy (ASE)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eToughness (T)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ePrevious problem: 7 -\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/8054-stress-strain-properties-7\\\"\u003e\u003cw:r\u003e\u003cw:t\u003etoughness\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"problem_search":{"errors":[],"problems":[{"id":8048,"title":"Stress-Strain Properties - 1","description":"This is the first in a series of problems regarding mechanics of materials, in particular, material properties drawn from stress-strain responses. A simplified typical stress-strain response is illustrated below (from quora.com):\r\n\r\nThe yield stress is the pressure required to start deformation of the material being tested. The yield point is the point along the response indicated by the yield stress (vertical axis) and the yield strain (horizontal axis). The response of the material up to this point is elastic, meaning that all deformation is reversible. The elastic modulus (E, also known as modulus of elasticity or Young's modulus) is the slope of this line. Write a function to calculate the elastic modulus for a material, provided the elastic strain and yield stress (yield point).\r\nNext problem: 2 - resilience.","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.440001px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none; white-space: normal; \"\u003e\u003cdiv style=\"block-size: 541px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 332px 270.5px; transform-origin: 332px 270.5px; vertical-align: baseline; \"\u003e\u003cdiv style=\"block-size: 63px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 31.5px; text-align: left; transform-origin: 309px 31.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eThis is the first in a series of problems regarding mechanics of materials, in particular, material properties drawn from stress-strain responses. A simplified typical stress-strain response is illustrated below (from\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e quora.com):\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 304px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 152px; text-align: center; transform-origin: 309px 152px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cimg class=\"imageNode\" style=\"vertical-align: baseline\" src=\"https://qph.cf2.quoracdn.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\" data-image-state=\"image-loaded\"\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 126px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 63px; text-align: left; transform-origin: 309px 63px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eThe yield stress is the pressure required to start deformation of the material being tested. The yield point is the point along the response indicated by the yield stress (vertical axis) and the yield strain (horizontal axis). The response of the material up to this point is elastic, meaning that all deformation is reversible. The elastic modulus (E, also known as modulus of elasticity or Young's modulus) is the slope of this line. Write a function to calculate the elastic modulus for a material, provided the elastic strain and yield stress (yield point).\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 21px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 10.5px; text-align: left; transform-origin: 309px 10.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eNext problem: 2 -\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e \u003c/span\u003e\u003c/span\u003e\u003ca target='_blank' href = \"https://www.mathworks.com/matlabcentral/cody/problems/8049-stress-strain-properties-2\"\u003e\u003cspan style=\"\"\u003e\u003cspan style=\"\"\u003eresilience\u003c/span\u003e\u003c/span\u003e\u003c/a\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003c/div\u003e\u003c/div\u003e","function_template":"function [E] = stress_strain1(S_y,e_y)\r\n\r\nE = 1;\r\n\r\nend\r\n","test_suite":"%% Note\r\n% The following properties are measured at room temperature and are tensile \r\n% in a single direction. Some materials, such as metals are generally\r\n% isotropic, whereas others, like composite are highly anisotropic\r\n% (different properties in different directions). Also, property values can\r\n% range depending on the material grade. Finally, thermal or environmental\r\n% changes can alter these properties, sometimes drastically.\r\n\r\n%% steel alloy (ASTM A36)\r\nS_y = 250e6; %Pa\r\nS_u = 400e6; %Pa\r\ne_y = 0.00125;\r\ne_u = 0.35;\r\nnu = 0.26;\r\nG = 79.3e9; %Pa\r\nE = 200e9; %Pa\r\ndensity = 7.85; %g/cm^3\r\nsh_exp = 0.14; %strain-hardening exponent\r\nsh_coeff = 0.463; %strain-hardening coefficient\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% titanium (Ti-6Al-4V)\r\nS_y = 830e6; %Pa\r\nS_u = 900e6; %Pa\r\ne_y = 0.00728;\r\ne_u = 0.14;\r\nnu = 0.342;\r\nG = 44e9; %Pa\r\nE = 114e9; %Pa\r\ndensity = 4.51; %g/cm^3\r\nsh_exp = 0.04; %strain-hardening exponent\r\nsh_coeff = 0.974; %strain-hardening coefficient\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% Inconel 718\r\nS_y = 1172e6; %Pa\r\nS_u = 1407e6; %Pa\r\ne_y = 0.00563;\r\ne_u = 0.027;\r\nnu = 0.29;\r\nG = 11.6e9; %Pa\r\nE = 208e9; %Pa\r\ndensity = 8.19; %g/cm^3\r\nsh_exp = 0.075; %strain-hardening exponent\r\nsh_coeff = 1.845; %strain-hardening coefficient\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% aluminum alloy (6061-T6)%^\u0026\r\nS_y = 241e6; %Pa\r\nS_u = 300e6; %Pa\r\ne_y = 0.0035;\r\ne_u = 0.15;\r\nnu = 0.33;\r\nG = 26e9; %Pa\r\nE = 68.9e9; %Pa\r\ndensity = 2.7; %g/cm^3\r\nsh_exp = 0.042; %strain-hardening exponent\r\nsh_coeff = 0.325; %strain-hardening coefficient\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% copper\r\nS_y = 70e6; %Pa\r\nS_u = 220e6; %Pa\r\ne_y = 0.00054;\r\ne_u = 0.48;\r\nnu = 0.34;\r\nG = 48e9; %Pa\r\nE = 130e9; %Pa\r\ndensity = 8.92; %g/cm^3\r\nsh_exp = 0.44; %strain-hardening exponent\r\nsh_coeff = 0.304; %strain-hardening coefficient 530MPa\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% rhenium\r\nS_y = 317e6; %Pa\r\nS_u = 1130e6; %Pa\r\ne_y = 0.000685;\r\ne_u = 0.24;\r\nnu = 0.3;\r\nG = 178e9; %Pa\r\nE = 463e9; %Pa\r\ndensity = 21.02; %g/cm^3\r\nsh_exp = 0.353; %strain-hardening exponent\r\nsh_coeff = 1.870; %strain-hardening coefficient\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% polymer (nylon, 6/6)\r\nS_y = 82e6; %Pa\r\nS_u = 82e6; %Pa\r\ne_y = 0.0265;\r\ne_u = 0.45;\r\nnu = 0.41;\r\nG = 2.8e9; %Pa\r\nE = 3.1e9; %Pa\r\ndensity = 1.14; %g/cm^3\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% polymer (nylon, 6/6) reinforced with 45wt.% glass fiber\r\nS_y = 230e6; %Pa\r\nS_u = 230e6; %Pa\r\ne_y = 0.016;\r\ne_u = 0.016;\r\nnu = 0.35;\r\nG = 13.0e9; %Pa\r\nE = 14.5e9; %Pa\r\ndensity = 1.51; %g/cm^3\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n\r\n%% diamond\r\nS_y = 1200e6; %Pa\r\nS_u = 1200e6; %Pa\r\ne_y = 0.001;\r\ne_u = 0.001;\r\nnu = 0.20;\r\nG = 478e9; %Pa\r\nE = 1200e9; %Pa\r\ndensity = 3.51; %g/cm^3\r\nassert(abs(stress_strain1(S_y,e_y)-E)\u003c1e9)\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":3,"created_by":26769,"edited_by":26769,"edited_at":"2024-03-27T17:40:39.000Z","deleted_by":null,"deleted_at":null,"solvers_count":324,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2015-03-30T18:09:31.000Z","updated_at":"2026-03-31T10:50:52.000Z","published_at":"2015-03-30T18:09:58.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThis is the first in a series of problems regarding mechanics of materials, in particular, material properties drawn from stress-strain responses. A simplified typical stress-strain response is illustrated below (from\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e quora.com):\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"center\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"verticalAlign\\\" w:val=\\\"baseline\\\"/\u003e\u003cw:attr w:name=\\\"altText\\\" w:val=\\\"\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId1\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe yield stress is the pressure required to start deformation of the material being tested. The yield point is the point along the response indicated by the yield stress (vertical axis) and the yield strain (horizontal axis). The response of the material up to this point is elastic, meaning that all deformation is reversible. The elastic modulus (E, also known as modulus of elasticity or Young's modulus) is the slope of this line. Write a function to calculate the elastic modulus for a material, provided the elastic strain and yield stress (yield point).\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eNext problem: 2 -\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"https://www.mathworks.com/matlabcentral/cody/problems/8049-stress-strain-properties-2\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eresilience\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\",\"relationship\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/image\",\"target\":\"/media/image1.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"relationshipId\":\"rId1\"}]},{\"partUri\":\"/media/image1.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"contentType\":\"image/net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"content\":\"https://qph.cf2.quoracdn.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"relationship\":null}],\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"target\":\"/matlab/document.xml\",\"relationshipId\":\"rId1\"}]}"},{"id":8052,"title":"Stress-Strain Properties - 5","description":"Similar to the previous problem, materials may be characterized by their stiffness-to-weight ratio, which is the elastic modulus divided by density. Write a function to calculate this ratio for a material provided its elastic modulus and density.\r\n\r\nPrevious problem: 4 - \u003chttp://www.mathworks.com/matlabcentral/cody/problems/8051-stress-strain-properties-4 strength-to-weight ratio\u003e. Next problem: 6 - \u003chttp://www.mathworks.com/matlabcentral/cody/problems/8053-stress-strain-properties-6 absorbed strain energy\u003e.","description_html":"\u003cp\u003eSimilar to the previous problem, materials may be characterized by their stiffness-to-weight ratio, which is the elastic modulus divided by density. Write a function to calculate this ratio for a material provided its elastic modulus and density.\u003c/p\u003e\u003cp\u003ePrevious problem: 4 - \u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/8051-stress-strain-properties-4\"\u003estrength-to-weight ratio\u003c/a\u003e. Next problem: 6 - \u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/8053-stress-strain-properties-6\"\u003eabsorbed strain energy\u003c/a\u003e.\u003c/p\u003e","function_template":"function [EtWR] = stress_strain5(E,density)\r\n\r\nEtWR = 1\r\n\r\nend\r\n","test_suite":"%% Note\r\n% The following properties are measured at room temperature and are tensile\r\n% in a single direction. Some materials, such as metals are generally\r\n% isotropic, whereas others, like composite are highly anisotropic\r\n% (different properties in different directions). Also, property values can\r\n% range depending on the material grade. Finally, thermal or environmental\r\n% changes can alter these properties, sometimes drastically.\r\n\r\n%% steel alloy (ASTM A36)\r\nS_y = 250e6; %Pa\r\nS_u = 400e6; %Pa\r\ne_y = 0.00125;\r\ne_u = 0.35;\r\nnu = 0.26;\r\nG = 79.3e9; %Pa\r\nE = 200e9; %Pa\r\ndensity = 7.85; %g/cm^3\r\nsh_exp = 0.14; %strain-hardening exponent\r\nsh_coeff = 0.463; %strain-hardening coefficient\r\nEtWR_corr = 2.548e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% titanium (Ti-6Al-4V)\r\nS_y = 830e6; %Pa\r\nS_u = 900e6; %Pa\r\ne_y = 0.00728;\r\ne_u = 0.14;\r\nnu = 0.342;\r\nG = 44e9; %Pa\r\nE = 114e9; %Pa\r\ndensity = 4.51; %g/cm^3\r\nsh_exp = 0.04; %strain-hardening exponent\r\nsh_coeff = 0.974; %strain-hardening coefficient\r\nEtWR_corr = 2.528e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% Inconel 718\r\nS_y = 1172e6; %Pa\r\nS_u = 1407e6; %Pa\r\ne_y = 0.00563;\r\ne_u = 0.027;\r\nnu = 0.29;\r\nG = 11.6e9; %Pa\r\nE = 208e9; %Pa\r\ndensity = 8.19; %g/cm^3\r\nsh_exp = 0.075; %strain-hardening exponent\r\nsh_coeff = 1.845; %strain-hardening coefficient\r\nEtWR_corr = 2.540e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% aluminum alloy (6061-T6)%^\u0026\r\nS_y = 241e6; %Pa\r\nS_u = 300e6; %Pa\r\ne_y = 0.0035;\r\ne_u = 0.15;\r\nnu = 0.33;\r\nG = 26e9; %Pa\r\nE = 68.9e9; %Pa\r\ndensity = 2.7; %g/cm^3\r\nsh_exp = 0.042; %strain-hardening exponent\r\nsh_coeff = 0.325; %strain-hardening coefficient\r\nEtWR_corr = 2.552e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% copper\r\nS_y = 70e6; %Pa\r\nS_u = 220e6; %Pa\r\ne_y = 0.00054;\r\ne_u = 0.48;\r\nnu = 0.34;\r\nG = 48e9; %Pa\r\nE = 130e9; %Pa\r\ndensity = 8.92; %g/cm^3\r\nsh_exp = 0.44; %strain-hardening exponent\r\nsh_coeff = 0.304; %strain-hardening coefficient\r\nEtWR_corr = 1.457e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% rhenium\r\nS_y = 317e6; %Pa\r\nS_u = 1130e6; %Pa\r\ne_y = 0.000685;\r\ne_u = 0.24;\r\nnu = 0.3;\r\nG = 178e9; %Pa\r\nE = 463e9; %Pa\r\ndensity = 21.02; %g/cm^3\r\nsh_exp = 0.353; %strain-hardening exponent\r\nsh_coeff = 1.870; %strain-hardening coefficient\r\nEtWR_corr = 2.203e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% polymer (nylon, 6/6)\r\nS_y = 82e6; %Pa\r\nS_u = 82e6; %Pa\r\ne_y = 0.0265;\r\ne_u = 0.45;\r\nnu = 0.41;\r\nG = 2.8e9; %Pa\r\nE = 3.1e9; %Pa\r\ndensity = 1.14; %g/cm^3\r\nEtWR_corr = 0.272e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% polymer (nylon, 6/6) reinforced with 45wt.% glass fiber\r\nS_y = 230e6; %Pa\r\nS_u = 230e6; %Pa\r\ne_y = 0.016;\r\ne_u = 0.016;\r\nnu = 0.35;\r\nG = 13.0e9; %Pa\r\nE = 14.5e9; %Pa\r\ndensity = 1.51; %g/cm^3\r\nEtWR_corr = 0.960e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%% diamond\r\nS_y = 1200e6; %Pa\r\nS_u = 1200e6; %Pa\r\ne_y = 0.001;\r\ne_u = 0.001;\r\nnu = 0.20;\r\nG = 478e9; %Pa\r\nE = 1200e9; %Pa\r\ndensity = 3.51; %g/cm^3\r\nEtWR_corr = 34.19e10;\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%%\r\nind = randi(4);\r\nswitch ind\r\n\tcase 1\r\n\t\tE = 114e9; %Pa\r\n\t\tdensity = 4.51; %g/cm^3\r\n\t\tEtWR_corr = 2.528e10;\r\n\tcase 2\r\n\t\tE = 68.9e9; %Pa\r\n\t\tdensity = 2.7; %g/cm^3\r\n\t\tEtWR_corr = 2.552e10;\r\n\tcase 3\r\n\t\tE = 200e9; %Pa\r\n\t\tdensity = 7.85; %g/cm^3\r\n\t\tEtWR_corr = 2.548e10;\r\n\tcase 4\r\n\t\tE = 1200e9; %Pa\r\n\t\tdensity = 3.51; %g/cm^3\r\n\t\tEtWR_corr = 34.19e10;\r\nend\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%%\r\nind = randi(4);\r\nswitch ind\r\n\tcase 1\r\n\t\tE = 68.9e9; %Pa\r\n\t\tdensity = 2.7; %g/cm^3\r\n\t\tEtWR_corr = 2.552e10;\r\n\tcase 2\r\n\t\tE = 3.1e9; %Pa\r\n\t\tdensity = 1.14; %g/cm^3\r\n\t\tEtWR_corr = 0.272e10;\r\n\tcase 3\r\n\t\tE = 14.5e9; %Pa\r\n\t\tdensity = 1.51; %g/cm^3\r\n\t\tEtWR_corr = 0.960e10;\r\n\tcase 4\r\n\t\tE = 208e9; %Pa\r\n\t\tdensity = 8.19; %g/cm^3\r\n\t\tEtWR_corr = 2.540e10;\r\nend\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n\r\n%%\r\nind = randi(4);\r\nswitch ind\r\n\tcase 1\r\n\t\tE = 208e9; %Pa\r\n\t\tdensity = 8.19; %g/cm^3\r\n\t\tEtWR_corr = 2.540e10;\r\n\tcase 2\r\n\t\tE = 463e9; %Pa\r\n\t\tdensity = 21.02; %g/cm^3\r\n\t\tEtWR_corr = 2.203e10;\r\n\tcase 3\r\n\t\tE = 130e9; %Pa\r\n\t\tdensity = 8.92; %g/cm^3\r\n\t\tEtWR_corr = 1.457e10;\r\n\tcase 4\r\n\t\tE = 3.1e9; %Pa\r\n\t\tdensity = 1.14; %g/cm^3\r\n\t\tEtWR_corr = 0.272e10;\r\nend\r\nassert(abs(stress_strain5(E,density)-EtWR_corr)/EtWR_corr\u003c1e-2)\r\n","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":26769,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":212,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2015-03-30T19:40:12.000Z","updated_at":"2026-03-10T20:42:38.000Z","published_at":"2015-03-30T19:40:12.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eSimilar to the previous problem, materials may be characterized by their stiffness-to-weight ratio, which is the elastic modulus divided by density. Write a function to calculate this ratio for a material provided its elastic modulus and density.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ePrevious problem: 4 -\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/8051-stress-strain-properties-4\\\"\u003e\u003cw:r\u003e\u003cw:t\u003estrength-to-weight ratio\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e. Next problem: 6 -\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/8053-stress-strain-properties-6\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eabsorbed strain energy\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":8049,"title":"Stress-Strain Properties - 2","description":"The resilience of a material is its ability to resist permanent (or plastic) deformation. The resilience coincides with the elastic region in the figure below and is calculated as the area under the stress-strain curve up to the yield point. Given that the elastic region is presumed to be entirely linear, this area is a triangle. Write a function to calculate the resilience of a material provided its elastic strain and yield stress (yield strength).\r\n\r\n(from quora.com)\r\nPrevious problem: 1 - elastic modulus. Next problem: 3 - qualitative measure of brittleness.","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.440001px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none; white-space: normal; \"\u003e\u003cdiv style=\"block-size: 478px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 332px 239px; transform-origin: 332px 239px; vertical-align: baseline; \"\u003e\u003cdiv style=\"block-size: 105px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 52.5px; text-align: left; transform-origin: 309px 52.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eThe resilience of a material is its ability to resist permanent (or plastic) deformation. The resilience coincides with the elastic region in the figure below and is calculated as the area under the stress-strain curve up to the yield point. Given that the elastic region is presumed to be entirely linear, this area is a triangle. Write a function to calculate the resilience of a material provided its elastic strain and yield stress (yield strength).\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 304px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 152px; text-align: center; transform-origin: 309px 152px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cimg class=\"imageNode\" style=\"vertical-align: baseline\" src=\"https://qph.cf2.quoracdn.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\" data-image-state=\"image-loaded\"\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 21px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 10.5px; text-align: center; transform-origin: 309px 10.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e(from quora.com)\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 21px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 309px 10.5px; text-align: left; transform-origin: 309px 10.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003ePrevious problem: 1 - \u003c/span\u003e\u003c/span\u003e\u003ca target='_blank' href = \"https://www.mathworks.com/matlabcentral/cody/problems/8048-stress-strain-properties-1\"\u003e\u003cspan style=\"\"\u003e\u003cspan style=\"\"\u003eelastic modulus\u003c/span\u003e\u003c/span\u003e\u003c/a\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e. Next problem: 3 -\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e \u003c/span\u003e\u003c/span\u003e\u003ca target='_blank' href = \"/#null\"\u003e\u003cspan style=\"\"\u003e\u003cspan style=\"\"\u003equalitative measure of brittleness\u003c/span\u003e\u003c/span\u003e\u003c/a\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003c/div\u003e\u003c/div\u003e","function_template":"function [R] = stress_strain2(S_y,e_y)\r\n\r\nR = 1;\r\n\r\nend\r\n","test_suite":"%% Note\r\n% The following properties are measured at room temperature and are tensile\r\n% in a single direction. Some materials, such as metals are generally\r\n% isotropic, whereas others, like composite are highly anisotropic\r\n% (different properties in different directions). Also, property values can\r\n% range depending on the material grade. Finally, thermal or environmental\r\n% changes can alter these properties, sometimes drastically.\r\n\r\n%% steel alloy (ASTM A36)\r\nS_y = 250e6; %Pa\r\nS_u = 400e6; %Pa\r\ne_y = 0.00125;\r\ne_u = 0.35;\r\nnu = 0.26;\r\nG = 79.3e9; %Pa\r\nE = 200e9; %Pa\r\ndensity = 7.85; %g/cm^3\r\nsh_exp = 0.14; %strain-hardening exponent\r\nsh_coeff = 0.463; %strain-hardening coefficient\r\nassert(abs(stress_strain2(S_y,e_y)-1.5625e5)/1.5625e5\u003c5e-2)\r\n\r\n%% titanium (Ti-6Al-4V)\r\nS_y = 830e6; %Pa\r\nS_u = 900e6; %Pa\r\ne_y = 0.00728;\r\ne_u = 0.14;\r\nnu = 0.342;\r\nG = 44e9; %Pa\r\nE = 114e9; %Pa\r\ndensity = 4.51; %g/cm^3\r\nsh_exp = 0.04; %strain-hardening exponent\r\nsh_coeff = 0.974; %strain-hardening coefficient\r\nassert(abs(stress_strain2(S_y,e_y)-3.0212e6)/3.0212e6\u003c5e-2)\r\n\r\n%% Inconel 718\r\nS_y = 1172e6; %Pa\r\nS_u = 1407e6; %Pa\r\ne_y = 0.00563;\r\ne_u = 0.027;\r\nnu = 0.29;\r\nG = 11.6e9; %Pa\r\nE = 208e9; %Pa\r\ndensity = 8.19; %g/cm^3\r\nsh_exp = 0.075; %strain-hardening exponent\r\nsh_coeff = 1.845; %strain-hardening coefficient\r\nassert(abs(stress_strain2(S_y,e_y)-3.29918e6)/3.29918e6\u003c5e-2)\r\n\r\n%% aluminum alloy (6061-T6)%^\u0026\r\nS_y = 241e6; %Pa\r\nS_u = 300e6; %Pa\r\ne_y = 0.0035;\r\ne_u = 0.15;\r\nnu = 0.33;\r\nG = 26e9; %Pa\r\nE = 68.9e9; %Pa\r\ndensity = 2.7; %g/cm^3\r\nsh_exp = 0.042; %strain-hardening exponent\r\nsh_coeff = 0.325; %strain-hardening coefficient\r\nassert(abs(stress_strain2(S_y,e_y)-4.2175e5)/4.2175e5\u003c5e-2)\r\n\r\n%% copper\r\nS_y = 70e6; %Pa\r\nS_u = 220e6; %Pa\r\ne_y = 0.00054;\r\ne_u = 0.48;\r\nnu = 0.34;\r\nG = 48e9; %Pa\r\nE = 130e9; %Pa\r\ndensity = 8.92; %g/cm^3\r\nsh_exp = 0.44; %strain-hardening exponent\r\nsh_coeff = 0.304; %strain-hardening coefficient 530MPa\r\nassert(abs(stress_strain2(S_y,e_y)-1.89e4)/1.89e4\u003c5e-2)\r\n\r\n%% rhenium\r\nS_y = 317e6; %Pa\r\nS_u = 1130e6; %Pa\r\ne_y = 0.000685;\r\ne_u = 0.24;\r\nnu = 0.3;\r\nG = 178e9; %Pa\r\nE = 463e9; %Pa\r\ndensity = 21.02; %g/cm^3\r\nsh_exp = 0.353; %strain-hardening exponent\r\nsh_coeff = 1.870; %strain-hardening coefficient\r\nassert(abs(stress_strain2(S_y,e_y)-1.085725e5)/1.085725e5\u003c5e-2)\r\n\r\n%% polymer (nylon, 6/6)\r\nS_y = 82e6; %Pa\r\nS_u = 82e6; %Pa\r\ne_y = 0.0265;\r\ne_u = 0.45;\r\nnu = 0.41;\r\nG = 2.8e9; %Pa\r\nE = 3.5e-2; %Pa\r\ndensity = 1.14; %g/cm^3\r\nassert(abs(stress_strain2(S_y,e_y)-1.0865e6)/1.0865e6\u003c5e-2)\r\n\r\n%% polymer (nylon, 6/6) reinforced with 45wt.% glass fiber\r\nS_y = 230e6; %Pa\r\nS_u = 230e6; %Pa\r\ne_y = 0.016;\r\ne_u = 0.016;\r\nnu = 0.35;\r\nG = 13.0e9; %Pa\r\nE = 14.5e9; %Pa\r\ndensity = 1.51; %g/cm^3\r\nassert(abs(stress_strain2(S_y,e_y)-1.84e6)/1.84e6\u003c5e-2)\r\n\r\n%% diamond\r\nS_y = 1200e6; %Pa\r\nS_u = 1200e6; %Pa\r\ne_y = 0.001;\r\ne_u = 0.001;\r\nnu = 0.20;\r\nG = 478e9; %Pa\r\nE = 1200e9; %Pa\r\ndensity = 3.51; %g/cm^3\r\nassert(abs(stress_strain2(S_y,e_y)-6e5)/6e5\u003c5e-2)\r\n\r\n%%\r\nind = randi(4);\r\nswitch ind\r\n\tcase 1\r\n\t\tS_y = 250e6; %Pa\r\n\t\te_y = 0.00125;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.5625e5)/1.5625e5\u003c5e-2)\r\n\tcase 2\r\n\t\tS_y = 82e6; %Pa\r\n\t\te_y = 0.0265;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.0865e6)/1.0865e6\u003c5e-2)\r\n\tcase 3\r\n\t\tS_y = 241e6; %Pa\r\n\t\te_y = 0.0035;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-4.2175e5)/4.2175e5\u003c5e-2)\r\n\tcase 4\r\n\t\tS_y = 1172e6; %Pa\r\n\t\te_y = 0.00563;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-3.29918e6)/3.29918e6\u003c5e-2)\r\nend\r\n\r\n%%\r\nind = randi(4);\r\nswitch ind\r\n\tcase 1\r\n\t\tS_y = 1200e6; %Pa\r\n\t\te_y = 0.001;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-6e5)/6e5\u003c5e-2)\r\n\tcase 2\r\n\t\tS_y = 1172e6; %Pa\r\n\t\te_y = 0.00563;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-3.29918e6)/3.29918e6\u003c5e-2)\r\n\tcase 3\r\n\t\tS_y = 230e6; %Pa\r\n\t\te_y = 0.016;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.84e6)/1.84e6\u003c5e-2)\r\n\tcase 4\r\n\t\tS_y = 250e6; %Pa\r\n\t\te_y = 0.00125;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.5625e5)/1.5625e5\u003c5e-2)\r\nend\r\n\r\n%%\r\nind = randi(4);\r\nswitch ind\r\n\tcase 1\r\n\t\tS_y = 830e6; %Pa\r\n\t\te_y = 0.00728;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-3.0212e6)/3.0212e6\u003c5e-2)\r\n\tcase 2\r\n\t\tS_y = 230e6; %Pa\r\n\t\te_y = 0.016;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.84e6)/1.84e6\u003c5e-2)\r\n\tcase 3\r\n\t\tS_y = 70e6; %Pa\r\n\t\te_y = 0.00054;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.89e4)/1.89e4\u003c5e-2)\r\n\tcase 4\r\n\t\tS_y = 317e6; %Pa\r\n\t\te_y = 0.000685;\r\n\t\tassert(abs(stress_strain2(S_y,e_y)-1.085725e5)/1.085725e5\u003c5e-2)\r\nend\r\n","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":26769,"edited_by":26769,"edited_at":"2024-03-27T17:41:09.000Z","deleted_by":null,"deleted_at":null,"solvers_count":264,"test_suite_updated_at":"2015-03-30T18:44:33.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2015-03-30T18:27:49.000Z","updated_at":"2026-03-31T10:53:49.000Z","published_at":"2015-03-30T18:27:49.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe resilience of a material is its ability to resist permanent (or plastic) deformation. The resilience coincides with the elastic region in the figure below and is calculated as the area under the stress-strain curve up to the yield point. Given that the elastic region is presumed to be entirely linear, this area is a triangle. Write a function to calculate the resilience of a material provided its elastic strain and yield stress (yield strength).\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"center\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"verticalAlign\\\" w:val=\\\"baseline\\\"/\u003e\u003cw:attr w:name=\\\"altText\\\" w:val=\\\"\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId1\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"center\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e(from quora.com)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ePrevious problem: 1 - \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"https://www.mathworks.com/matlabcentral/cody/problems/8048-stress-strain-properties-1\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eelastic modulus\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e. Next problem: 3 -\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"\\\"\u003e\u003cw:r\u003e\u003cw:t\u003equalitative measure of brittleness\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\",\"relationship\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/image\",\"target\":\"/media/image1.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"relationshipId\":\"rId1\"}]},{\"partUri\":\"/media/image1.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"contentType\":\"image/net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"content\":\"https://qph.cf2.quoracdn.net/main-qimg-b2693f4b9ea8430af25df920757e0b29-lq\",\"relationship\":null}],\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"target\":\"/matlab/document.xml\",\"relationshipId\":\"rId1\"}]}"},{"id":8055,"title":"Stress-Strain Properties - 8","description":"Up to this point, you've calculated some material properties based on tensile stress-strain data. For this problem, you are tasked with writing a function to calculate all of these properties and gather them, along with supplied properties, such as strain values, into an array. You'll be provided a cell array of strings in the function template; you must return an accompanying numerical array that contains all the specified properties. Below is the list of properties for a material, both supplied and calculated, that make up the array (with variable names that have been used):\r\n\r\n* Yield Strength (S_y)\r\n* Yield Strain (e_y)\r\n* Ultimate Strength (S_u)\r\n* Failure Strain (e_u)\r\n* Poisson's Ratio (nu)\r\n* Shear Modulus (G)\r\n* Elastic Modulus (E)\r\n* Density\r\n* Strain-hardening Exponent (sh_exp)\r\n* Strain-hardening Coefficient (sh_coeff)\r\n* Resilience (R)\r\n* Strength-to-weight Ratio (StWR)\r\n* Stiffness-to-weight Ratio (EtWR)\r\n* Absorbed Strain Energy (ASE)\r\n* Toughness (T)\r\n\r\nPrevious problem: 7 - \u003chttp://www.mathworks.com/matlabcentral/cody/problems/8054-stress-strain-properties-7 toughness\u003e.","description_html":"\u003cp\u003eUp to this point, you've calculated some material properties based on tensile stress-strain data. For this problem, you are tasked with writing a function to calculate all of these properties and gather them, along with supplied properties, such as strain values, into an array. You'll be provided a cell array of strings in the function template; you must return an accompanying numerical array that contains all the specified properties. Below is the list of properties for a material, both supplied and calculated, that make up the array (with variable names that have been used):\u003c/p\u003e\u003cul\u003e\u003cli\u003eYield Strength (S_y)\u003c/li\u003e\u003cli\u003eYield Strain (e_y)\u003c/li\u003e\u003cli\u003eUltimate Strength (S_u)\u003c/li\u003e\u003cli\u003eFailure Strain (e_u)\u003c/li\u003e\u003cli\u003ePoisson's Ratio (nu)\u003c/li\u003e\u003cli\u003eShear Modulus (G)\u003c/li\u003e\u003cli\u003eElastic Modulus (E)\u003c/li\u003e\u003cli\u003eDensity\u003c/li\u003e\u003cli\u003eStrain-hardening Exponent (sh_exp)\u003c/li\u003e\u003cli\u003eStrain-hardening Coefficient (sh_coeff)\u003c/li\u003e\u003cli\u003eResilience (R)\u003c/li\u003e\u003cli\u003eStrength-to-weight Ratio (StWR)\u003c/li\u003e\u003cli\u003eStiffness-to-weight Ratio (EtWR)\u003c/li\u003e\u003cli\u003eAbsorbed Strain Energy (ASE)\u003c/li\u003e\u003cli\u003eToughness (T)\u003c/li\u003e\u003c/ul\u003e\u003cp\u003ePrevious problem: 7 - \u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/8054-stress-strain-properties-7\"\u003etoughness\u003c/a\u003e.\u003c/p\u003e","function_template":"function [arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff)\r\n\r\narr_descr = {\r\n\t'Yield Strength','Yield Strain','Ultimate Strength','Failure Strain',...\r\n\t'Poisson''s Ratio','Shear Modulus','Elastic Modulus','Density',...\r\n\t'Strain-hardening Exponent','Strain-hardening Coefficient',...\r\n\t'Resilience','Strength-to-weight Ratio','Stiffness-to-weight Ratio',...\r\n\t'Absorbed Strain Energy','Toughness';\r\n};\r\n\r\narr_vals = [\r\n\t1;\r\n];\r\n\r\nend\r\n","test_suite":"%% Note\r\n% The following properties are measured at room temperature and are tensile\r\n% in a single direction. Some materials, such as metals are generally\r\n% isotropic, whereas others, like composite are highly anisotropic\r\n% (different properties in different directions). Also, property values can\r\n% range depending on the material grade. Finally, thermal or environmental\r\n% changes can alter these properties, sometimes drastically.\r\n\r\n%% steel alloy (ASTM A36)\r\nS_y = 250e6; %Pa\r\nS_u = 400e6; %Pa\r\ne_y = 0.00125;\r\ne_u = 0.35;\r\nnu = 0.26; %Poisson's ratio\r\nG = 79.3e9; %Pa (shear modulus)\r\nE = 200e9; %Pa  (elastic modulus)\r\ndensity = 7.85; %g/cm^3\r\nsh_exp = 0.14; %strain-hardening exponent\r\nsh_coeff = 463e6; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t1.5625e5, 5.096e7, 2.548e10, 12.28e7, 12.26e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% titanium (Ti-6Al-4V)\r\nS_y = 830e6; %Pa\r\nS_u = 900e6; %Pa\r\ne_y = 0.00728;\r\ne_u = 0.14;\r\nnu = 0.342;\r\nG = 44e9; %Pa\r\nE = 114e9; %Pa\r\ndensity = 4.51; %g/cm^3\r\nsh_exp = 0.04; %strain-hardening exponent\r\nsh_coeff = 974e6; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t3.0212e6, 19.96e7, 2.528e10, 12.12e7, 11.82e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% Inconel 718\r\nS_y = 1172e6; %Pa\r\nS_u = 1407e6; %Pa\r\ne_y = 0.00563;\r\ne_u = 0.027;\r\nnu = 0.29;\r\nG = 11.6e9; %Pa\r\nE = 208e9; %Pa\r\ndensity = 8.19; %g/cm^3\r\nsh_exp = 0.075; %strain-hardening exponent\r\nsh_coeff = 1845e6; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t3.29918e6, 17.18e7, 2.540e10, 3.535e7, 3.205e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% aluminum alloy (6061-T6)%^\u0026\r\nS_y = 241e6; %Pa\r\nS_u = 300e6; %Pa\r\ne_y = 0.0035;\r\ne_u = 0.15;\r\nnu = 0.33;\r\nG = 26e9; %Pa\r\nE = 68.9e9; %Pa\r\ndensity = 2.7; %g/cm^3\r\nsh_exp = 0.042; %strain-hardening exponent\r\nsh_coeff = 325e6; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t4.2175e5, 11.11e7, 2.552e10, 4.321e7, 4.279e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% copper\r\nS_y = 70e6; %Pa\r\nS_u = 220e6; %Pa\r\ne_y = 0.00054;\r\ne_u = 0.48;\r\nnu = 0.34;\r\nG = 48e9; %Pa\r\nE = 130e9; %Pa\r\ndensity = 8.92; %g/cm^3\r\nsh_exp = 0.44; %strain-hardening exponent\r\nsh_coeff = 304e6; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t1.89e4, 2.466e7, 1.457e10, 7.342e7, 7.340e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% rhenium\r\nS_y = 317e6; %Pa\r\nS_u = 1130e6; %Pa\r\ne_y = 0.000685;\r\ne_u = 0.24;\r\nnu = 0.3;\r\nG = 178e9; %Pa\r\nE = 463e9; %Pa\r\ndensity = 21.02; %g/cm^3\r\nsh_exp = 0.353; %strain-hardening exponent\r\nsh_coeff = 1870e6; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t1.085725e5, 5.376e7, 2.203e10, 20.06e7, 20.05e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% polymer (nylon, 6/6)\r\nS_y = 82e6; %Pa\r\nS_u = 82e6; %Pa\r\ne_y = 0.0265;\r\ne_u = 0.45;\r\nnu = 0.41;\r\nG = 2.8e9; %Pa\r\nE = 3.1e9; %Pa\r\ndensity = 1.14; %g/cm^3\r\nsh_exp = 0; %strain-hardening exponent\r\nsh_coeff = 0; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t1.0865e6, 7.193e7, 0.272e10, 3.581e7, 3.473e7];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\ndiffs(isnan(diffs)) = 0;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% polymer (nylon, 6/6) reinforced with 45wt.% glass fiber\r\nS_y = 230e6; %Pa\r\nS_u = 230e6; %Pa\r\ne_y = 0.016;\r\ne_u = 0.016;\r\nnu = 0.35;\r\nG = 13.0e9; %Pa\r\nE = 14.5e9; %Pa\r\ndensity = 1.51; %g/cm^3\r\nsh_exp = 0; %strain-hardening exponent\r\nsh_coeff = 0; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t1.84e6, 15.23e7, 0.960e10, 0.184e7, 0];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\ndiffs(isnan(diffs)) = 0;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n\r\n%% diamond\r\nS_y = 1200e6; %Pa\r\nS_u = 1200e6; %Pa\r\ne_y = 0.001;\r\ne_u = 0.001;\r\nnu = 0.20;\r\nG = 478e9; %Pa\r\nE = 1200e9; %Pa\r\ndensity = 3.51; %g/cm^3\r\nsh_exp = 0; %strain-hardening exponent\r\nsh_coeff = 0; %strain-hardening coefficient\r\n[arr_vals] = stress_strain8(S_y,S_u,e_y,e_u,nu,G,E,density,sh_exp,sh_coeff);\r\narr_vals_corr = [S_y, e_y, S_u, e_u, nu, G, E, density, sh_exp, sh_coeff,...\r\n\t6e5, 34.19e7, 34.19e10, 0.06e7, 0];\r\ndiffs = abs(arr_vals-arr_vals_corr)./arr_vals_corr;\r\ndiffs(isnan(diffs)) = 0;\r\nfor i = 1:numel(diffs)\r\n\tassert(diffs(i)\u003c1e-2)\r\nend\r\n","published":true,"deleted":false,"likes_count":0,"comments_count":0,"created_by":26769,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":48,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2015-03-31T02:36:58.000Z","updated_at":"2026-02-19T09:49:12.000Z","published_at":"2015-03-31T02:36:58.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eUp to this point, you've calculated some material properties based on tensile stress-strain data. For this problem, you are tasked with writing a function to calculate all of these properties and gather them, along with supplied properties, such as strain values, into an array. You'll be provided a cell array of strings in the function template; you must return an accompanying numerical array that contains all the specified properties. Below is the list of properties for a material, both supplied and calculated, that make up the array (with variable names that have been used):\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYield Strength (S_y)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYield Strain (e_y)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eUltimate Strength (S_u)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFailure Strain (e_u)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ePoisson's Ratio (nu)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eShear Modulus (G)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId 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