Problem 966. Bisection method of finding a root.

Solution 159107

Submitted on 7 Nov 2012 by Jean-Marie Sainthillier

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Test	Status	Code Input and Output
1	Pass	f=@(x) x.^2-4; x_lower = 1; x_upper = 3; es = 0; maxit=1; x_root_correct = 2; assert(isequal(bisection(f,x_lower,x_upper,es,maxit),x_root_correct))
2	Pass	f=@(x) x.^2-4; x_lower = 1; x_upper = 4; es = 0; maxit=1; x_root = 2.5; assert(isequal(bisection(f,x_lower,x_upper,es,maxit),x_root))
3	Pass	f=@(x) x.^2-4; x_lower = 1; x_upper = 4; x_root = 2.000000476837158; assert(isequal(bisection(f,x_lower,x_upper),x_root))

Test

Status

Code Input and Output

Pass

f=@(x) x.^2-4; x_lower = 1; x_upper = 3; es = 0; maxit=1; x_root_correct = 2; assert(isequal(bisection(f,x_lower,x_upper,es,maxit),x_root_correct))

Pass

f=@(x) x.^2-4; x_lower = 1; x_upper = 4; es = 0; maxit=1; x_root = 2.5; assert(isequal(bisection(f,x_lower,x_upper,es,maxit),x_root))

Pass

f=@(x) x.^2-4; x_lower = 1; x_upper = 4; x_root = 2.000000476837158; assert(isequal(bisection(f,x_lower,x_upper),x_root))

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