Cody

# Problem 81. Mandelbrot Numbers

Solution 2943

Submitted on 26 Jan 2012 by @bmtran (Bryant Tran)
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### Test Suite

Test Status Code Input and Output
1   Pass
%% C = 0; lim = 5; N_correct = 5; assert(isequal(mandelbrot(C,lim),N_correct))

Z = 0 Z = 0 Z = 0 Z = 0 Z = 0 Z = 0

2   Pass
%% C = [0 0.5; 1 4]; lim = 5; N_correct = [5 4; 2 1]; assert(isequal(mandelbrot(C,lim),N_correct))

Z = 0 0.5000 1.0000 4.0000 Z = 0 0.7500 2.0000 4.0000 Z = 0 1.0625 5.0000 4.0000 Z = 0 1.6289 5.0000 4.0000 Z = 0 3.1533 5.0000 4.0000 Z = 0 3.1533 5.0000 4.0000

3   Pass
%% i = sqrt(-1); C = [i 1 -2*i -2]; lim = 10; N_correct = [10 2 1 10]; assert(isequal(mandelbrot(C,lim),N_correct))

Z = Columns 1 through 3 0 + 1.0000i 1.0000 0 - 2.0000i Column 4 -2.0000 Z = Columns 1 through 3 -1.0000 + 1.0000i 2.0000 -4.0000 - 2.0000i Column 4 2.0000 Z = Columns 1 through 3 0 - 1.0000i 5.0000 -4.0000 - 2.0000i Column 4 2.0000 Z = Columns 1 through 3 -1.0000 + 1.0000i 5.0000 -4.0000 - 2.0000i Column 4 2.0000 Z = Columns 1 through 3 0 - 1.0000i 5.0000 -4.0000 - 2.0000i Column 4 2.0000 Z = Columns 1 through 3 -1.0000 + 1.0000i 5.0000 -4.0000 - 2.0000i Column 4 2.0000 Z = Columns 1 through 3 0 - 1.0000i 5.0000 -4.0000 - 2.0000i Column 4 2.0000 Z = Columns 1 through 3 -1.0000 + 1.0000i 5.0000 -4.0000 - 2.0000i Column 4 2.0000 Z = Columns 1 through 3 0 - 1.0000i 5.0000 -4.0000 - 2.0000i Column 4 2.0000 Z = Columns 1 through 3 -1.0000 + 1.0000i 5.0000 -4.0000 - 2.0000i Column 4 2.0000 Z = Columns 1 through 3 0 - 1.0000i 5.0000 -4.0000 - 2.0000i Column 4 2.0000