Cody

Problem 44500. Find the starting index of a consecutive condition

Solution 1419086

Submitted on 17 Jan 2018 by Tim
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.
Solve This Problem View on Solution Map

Test Suite

Test Status Code Input and Output
1   Pass
v = logical([0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0]); n = 1; i = consecutiveFind(v, n); i_correct = 2; assert(isequal(i, i_correct))
2   Pass
v = logical([0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0]); n = 4; i = consecutiveFind(v, n); i_correct = 6; assert(isequal(i, i_correct))
3   Pass
v = logical([0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0]); n = 6; i = consecutiveFind(v, n); assert(isempty(i))
4   Pass
v = false(1, 10); n = 1; i = consecutiveFind(v, n); assert(isempty(i))
5   Pass
x = 0 : pi/4 : 2*pi; v = sin(x) < 1; n = 5; i = consecutiveFind(v, n); i_correct = 4; assert(isequal(i, i_correct))

Suggested Problems

More from this Author25

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!