Cody

Problem 44364. Is this a valid Tic Tac Toe State?

Solution 1324270

Submitted on 2 Nov 2017 by Eric G.
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.
Solve This Problem View on Solution Map

Test Suite

Test Status Code Input and Output
1   Pass
x = [1 1 0 0 0 0 0 0 0]; y_correct = 0; assert(isequal(isLegalTicTacToeState(x),y_correct))

sumGrp = 2 0 0 1 1 0 1 0
2   Pass
x = [0 0 0 0 0 0 0 0 0]; y_correct = 1; assert(isequal(isLegalTicTacToeState(x),y_correct))

sumGrp = 0 0 0 0 0 0 0 0
3   Pass
x = [ -1 1 1 1 -1 -1 1 -1 -1]; y_correct = 0; assert(isequal(isLegalTicTacToeState(x),y_correct))

sumGrp = 1 -1 -1 1 -1 -1 -3 1
4   Pass
x = [ 0 -1 1 -1 1 0 1 0 0]; y_correct = 1; assert(isequal(isLegalTicTacToeState(x),y_correct))

sumGrp = 0 0 1 0 0 1 1 3
5   Pass
x = [ 1 1 1 -1 -1 -1 0 0 0]; y_correct = 0; assert(isequal(isLegalTicTacToeState(x),y_correct))

sumGrp = 3 -3 0 0 0 0 0 0
6   Pass
x = [-1 1 1 0 -1 1 1 0 -1]; y_correct = 0; assert(isequal(isLegalTicTacToeState(x),y_correct))

sumGrp = 1 0 0 0 0 1 -3 1
7   Pass
x = [-1 1 0 0 0 0 0 0 0]; y_correct = 1; assert(isequal(isLegalTicTacToeState(x),y_correct))

sumGrp = 0 0 0 -1 1 0 -1 0
8   Pass
x = [-1 0 0 0 0 0 0 0 0]; y_correct = 0; assert(isequal(isLegalTicTacToeState(x),y_correct))

sumGrp = -1 0 0 -1 0 0 -1 0
9   Pass
x = [-1 1 0 0 1 0 0 1 0]; y_correct = 0; assert(isequal(isLegalTicTacToeState(x),y_correct))

sumGrp = 0 1 1 -1 3 0 0 1
10   Pass
x = [1 1 1 -1 1 -1 -1 1 -1]; y_correct = 1; assert(isequal(isLegalTicTacToeState(x),y_correct))

sumGrp = 3 -1 -1 -1 3 -1 1 1

Suggested Problems

More from this Author52

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!