Cody

# Problem 44359. 5th Time's a Charm

Solution 1357499

Submitted on 26 Nov 2017 by David Verrelli
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.

### Test Suite

Test Status Code Input and Output
1   Pass
x = 1; y1 = fifth_times_a_charm(x); assert(~isequal(y1,x)) y2 = fifth_times_a_charm(x); assert(~isequal(y2,x)) assert(abs(x-y2)<abs(x-y1)) y3 = fifth_times_a_charm(x); assert(~isequal(y3,x)) assert(abs(x-y3)<abs(x-y2)) y4 = fifth_times_a_charm(x); assert(~isequal(y4,x)) assert(abs(x-y4)<abs(x-y3)) y5 = fifth_times_a_charm(x); assert(isequal(y5,x))

count = 1 x_old = 1 y_old = 6 y = 5 count = 2 y = 4 count = 3 y = 3 count = 4 y = 2 count = 5 y = 1

2   Pass
x = -1; y1 = fifth_times_a_charm(x); assert(~isequal(y1,x)) y2 = fifth_times_a_charm(x); assert(~isequal(y2,x)) assert(abs(x-y2)<abs(x-y1)) y3 = fifth_times_a_charm(x); assert(~isequal(y3,x)) assert(abs(x-y3)<abs(x-y2)) y4 = fifth_times_a_charm(x); assert(~isequal(y4,x)) assert(abs(x-y4)<abs(x-y3)) y5 = fifth_times_a_charm(x); assert(isequal(y5,x))

count = 1 x_old = -1 y_old = 4 y = 3 count = 2 y = 2 count = 3 y = 1 count = 4 y = 0 count = 5 y = -1

3   Pass
x = 42; y1 = fifth_times_a_charm(x); assert(~isequal(y1,x)) y2 = fifth_times_a_charm(x); assert(~isequal(y2,x)) assert(abs(x-y2)<abs(x-y1)) y3 = fifth_times_a_charm(x); assert(~isequal(y3,x)) assert(abs(x-y3)<abs(x-y2)) y4 = fifth_times_a_charm(x); assert(~isequal(y4,x)) assert(abs(x-y4)<abs(x-y3)) y5 = fifth_times_a_charm(x); assert(isequal(y5,x))

count = 1 x_old = 42 y_old = 47 y = 46 count = 2 y = 45 count = 3 y = 44 count = 4 y = 43 count = 5 y = 42

4   Pass
x = i; y1 = fifth_times_a_charm(x); assert(~isequal(y1,x)) y2 = fifth_times_a_charm(x); assert(~isequal(y2,x)) assert(abs(x-y2)<abs(x-y1)) y3 = fifth_times_a_charm(x); assert(~isequal(y3,x)) assert(abs(x-y3)<abs(x-y2)) y4 = fifth_times_a_charm(x); assert(~isequal(y4,x)) assert(abs(x-y4)<abs(x-y3)) y5 = fifth_times_a_charm(x); assert(isequal(y5,x))

count = 1 x_old = 0.0000 + 1.0000i y_old = 5.0000 + 1.0000i y = 4.0000 + 1.0000i count = 2 y = 3.0000 + 1.0000i count = 3 y = 2.0000 + 1.0000i count = 4 y = 1.0000 + 1.0000i count = 5 y = 0.0000 + 1.0000i