Cody

# Problem 43. Subset Sum

Solution 36665

Submitted on 10 Feb 2012 by Jean-Yves Tinevez
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### Test Suite

Test Status Code Input and Output
1   Pass
%% v = [2, 3, 5]; n = 8; correct = [2, 3]; actual = subset_sum(v, n); assert(isequal(actual, correct))

m = 8 d = 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1 i = 3 ind = 2 3

2   Pass
%% v = [5, 3, 2]; n = 2; correct = 3; actual = subset_sum(v, n); assert(isequal(actual, correct))

m = 8 d = 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1 i = 1 ind = 3

3   Pass
%% v = [2, 3, 5]; n = 4; correct = []; actual = subset_sum(v, n); assert(isequal(actual, correct))

m = 8 d = 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1 i = Empty matrix: 0-by-1 ind = Empty matrix: 0-by-1 ind = []

4   Pass
%% v = [1, 1, 1, 1, 1]; n = 5; correct = [1, 2, 3, 4, 5]; actual = subset_sum(v, n); assert(isequal(actual, correct))

m = 32 d = 0 0 0 0 1 0 0 0 1 0 0 0 0 1 1 0 0 1 0 0 0 0 1 0 1 0 0 1 1 0 0 0 1 1 1 0 1 0 0 0 0 1 0 0 1 0 1 0 1 0 0 1 0 1 1 0 1 1 0 0 0 1 1 0 1 0 1 1 1 0 0 1 1 1 1 1 0 0 0 0 1 0 0 0 1 1 0 0 1 0 1 0 0 1 1 1 0 1 0 0 1 0 1 0 1 1 0 1 1 0 1 0 1 1 1 1 1 0 0 0 1 1 0 0 1 1 1 0 1 0 1 1 0 1 1 1 1 1 0 0 1 1 1 0 1 1 1 1 1 0 1 1 1 1 1 i = 31 ind = 1 2 3 4 5

5   Pass
%% v = [1, 2, 3, 4, 100]; n = 100; correct = 5; actual = subset_sum(v, n); assert(isequal(actual, correct))

m = 32 d = 0 0 0 0 1 0 0 0 1 0 0 0 0 1 1 0 0 1 0 0 0 0 1 0 1 0 0 1 1 0 0 0 1 1 1 0 1 0 0 0 0 1 0 0 1 0 1 0 1 0 0 1 0 1 1 0 1 1 0 0 0 1 1 0 1 0 1 1 1 0 0 1 1 1 1 1 0 0 0 0 1 0 0 0 1 1 0 0 1 0 1 0 0 1 1 1 0 1 0 0 1 0 1 0 1 1 0 1 1 0 1 0 1 1 1 1 1 0 0 0 1 1 0 0 1 1 1 0 1 0 1 1 0 1 1 1 1 1 0 0 1 1 1 0 1 1 1 1 1 0 1 1 1 1 1 i = 1 ind = 5

6   Pass
%% v = [-7, -3, -2, 8, 5]; n = 0; correct = [2, 3, 5]; actual = subset_sum(v, n); assert(isequal(actual, correct))

m = 32 d = 0 0 0 0 1 0 0 0 1 0 0 0 0 1 1 0 0 1 0 0 0 0 1 0 1 0 0 1 1 0 0 0 1 1 1 0 1 0 0 0 0 1 0 0 1 0 1 0 1 0 0 1 0 1 1 0 1 1 0 0 0 1 1 0 1 0 1 1 1 0 0 1 1 1 1 1 0 0 0 0 1 0 0 0 1 1 0 0 1 0 1 0 0 1 1 1 0 1 0 0 1 0 1 0 1 1 0 1 1 0 1 0 1 1 1 1 1 0 0 0 1 1 0 0 1 1 1 0 1 0 1 1 0 1 1 1 1 1 0 0 1 1 1 0 1 1 1 1 1 0 1 1 1 1 1 i = 13 ind = 2 3 5

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