Problem 365. Numbers with prime factors 2, 3 and 5.

Solution 1978792

Submitted on 16 Oct 2019

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Test	Status	Code Input and Output
1	Pass	n = 2; A_correct = 2; assert(isequal(your_fcn_name(n),A_correct)) A = 2
2	Pass	n = 3; A_correct = [2 3]; assert(isequal(your_fcn_name(n),A_correct)) A = 2 3
3	Pass	n = 4; A_correct = [2 3 4]; assert(isequal(your_fcn_name(n),A_correct)) A = 2 3 4
4	Pass	n = 5; A_correct = [2 3 4 5]; assert(isequal(your_fcn_name(n),A_correct)) A = 2 3 4 5
5	Pass	n = 10; A_correct = [2 3 4 5 6 8 9 10]; assert(isequal(your_fcn_name(n),A_correct)) A = 2 3 4 5 6 8 9 10
6	Fail	n = 17; A_correct = [2 3 4 5 6 8 9 10 12 15 16]; assert(isequal(your_fcn_name(n),A_correct)) A = 2 3 4 5 6 8 9 10 12 14 15 16 Assertion failed.
7	Fail	n = 31; A_correct = [2 3 4 5 6 8 9 10 12 15 16 18 20 24 25 27 30]; assert(isequal(your_fcn_name(n),A_correct)) A = 2 3 4 5 6 8 9 10 12 14 15 16 18 20 21 22 24 25 26 27 28 30 Assertion failed.