Cody

# Problem 32. Most nonzero elements in row

Solution 187135

Submitted on 7 Jan 2013 by Vialla
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### Test Suite

Test Status Code Input and Output
1   Pass
%% a = [ ... 1 2 0 0 0 0 0 5 0 0 2 7 0 0 0 0 6 9 3 3]; r_correct = 4; assert(isequal(fullest_row(a),r_correct))

c = 1 1 NaN NaN NaN NaN NaN 1 NaN NaN 1 1 NaN NaN NaN NaN 1 1 1 1 b = 0 0 1 1 1 1 1 0 1 1 0 0 1 1 1 1 0 0 0 0 c = 1 1 0 0 0 0 0 1 0 0 1 1 0 0 0 0 1 1 1 1 truc = 4 bidule = 4 r = 4

2   Pass
%% a = [ ... 1 2 0 0 0 0 5 0 0 6 9 -3 2 7 0 0 0 0 0 0]; r_correct = 3; assert(isequal(fullest_row(a),r_correct))

c = 1 1 NaN NaN NaN NaN 1 NaN NaN 1 1 1 1 1 NaN NaN NaN NaN NaN NaN b = 0 0 1 1 1 1 0 1 1 0 0 0 0 0 1 1 1 1 1 1 c = 1 1 0 0 0 0 1 0 0 1 1 1 1 1 0 0 0 0 0 0 truc = 3 bidule = 3 r = 3

3   Pass
%% a = [ ... 1 0 0 0 0 0 0 0 0 0 0 0 0 2 3]; r_correct = 5; assert(isequal(fullest_row(a),r_correct))

c = 1 NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN 1 1 b = 0 1 1 1 1 1 1 1 1 1 1 1 1 0 0 c = 1 0 0 0 0 0 0 0 0 0 0 0 0 1 1 truc = 2 bidule = 5 r = 5

4   Pass
%% a = [ ... 0 0 0 -3 0 0]; r_correct = 4; assert(isequal(fullest_row(a),r_correct))

c = NaN NaN NaN 1 NaN NaN b = 1 1 1 0 1 1 c = 0 0 0 1 0 0 truc = 1 bidule = 4 r = 4