yes of course. Leading solution:
function b = matInc(a)
[b aa] = ndgrid(1:max(a), a);
b(b > aa) = 0;
Check to see if a Sudoku Puzzle is Solved
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Matrix which contains the values of an other matrix A at the given locations.
Find the elements of a matrix according to a defined property.
A quadrant matrix
Create a matrix X, where each column is a shifted copy of the vector v
Remove NaN ?
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